Question

Helpppppp pllzzzzzzzzz

Answer 1

Answer:

The length of side of largest square is 15 inches

Step-by-step explanation:

The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.

Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.

So,

Area of square 1: 81 square inches

$s^2 = A\\s^2 = 81\\\sqrt{s^2} = \sqrt{81}\\s = 9$

Perimeter of square 2: 48 inches

$4*side = P\\4* side = 48\\side = \frac{48}{4}\\side = 12\ inches$

We can see that a right angled triangle is formed.

Here

Base = 12 inches

Perpendicular = 9 inches

And the side of largest square will be hypotenuse.

Pythagoras theorem can be used to find the length.

$(H)^2 = (P)^2+(B)^2\\H^2 = (9)^2+(12)^2\\H^2 = 81+144\\H^2 = 225\\\sqrt{H^2} = \sqrt{225}\\H = 15$

Hence,

The length of side of largest square is 15 inches