All categories

3 years ago

Given that (0, 3) is on the graph of f (x) find the corresponding point for the function f (x) - 2

Mathematics

1 answer:

zheka24 [161]3 years ago

7 0

Answer:

(0,1)

Step-by-step explanation:

Let (0,3) lies on f(x), then:

$f(0) = 3$

Let

$g(x) = f(x) - 2$

To find the corresponding point that lie on g(x), we substitute x=0

This implies that:

$g(0) = f(0) - 2$

But f(0)=3

We substitute to get:

$g(0) = 3 - 2 = 1$

The required point is (0,1)

You might be interested in

What is the answer to this question?

melisa1 [442]

Answer: I think it is negative.

Step-by-step explanation: When you add a negative to a negative you still have a negative.

7 0

4 years ago

How many times greater is 1 1/2 then 1/4

Vlad [161]

6 times

6 * 1/4 is 6/4
6/4 is 1 2/4 which is 1 1/2

6 0

3 years ago

Given that lines m and n are parallel and that line t is a transversal, the

Naily [24]

Answer:

Step-by-step explanation:

if the opposite of <1 is 120 and the line it is sitting on is flat, we can figure out that both connected would be 180

the equation would be 180-120=60

hope this helped

3 0

3 years ago

Read 2 more answers

The sum of three consecutive even numbers is 96. What is the smallest of the three numbers

lidiya [134]

The answer is 30.

First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.

This may help:

96/3=32

32 + 32 + 32 = 96
(32-2)+(32+0)+(32+2)=96
30+32+34=93

8 0

3 years ago

If a cup of coffee has temperature 97Â°C in a room where the ambient air temperature is 25Â°C, then, according to Newton's Law o

FinnZ [79.3K]

Answer:

The average temperature is $T_{a} = 81.95^oC$

Step-by-step explanation:

From the question we are told that

The temperature of the coffee after time t is $T(t) = 25 + 72 e^{[-\frac{t}{45} ]}$

Now the average temperature during the first 22 minutes i.e fro $0 \to 22$ minutes is mathematically evaluated as

$T_{a} = \frac{1}{22-0} \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx$

$T_{a} = \frac{1}{22} [25 t + 72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.$

$T_{a} = \frac{1}{22} [25 t - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.$

$T_{a} = \frac{1}{22} [25 (22) - 3240e^{[-\frac{22}{45} ]} - (- 3240e^{0} )]$

$T_{a} = \frac{1}{22} [550 - 1987.12 + 3240]$

$T_{a} = 81.95^oC$

8 0

3 years ago