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2 years ago

10

If the circumference of a wheel is 94 cm what is its approximate diameter

1 answer:

Aleks [24]2 years ago

6 0

Hey there :)

We know the formula for the circumference of a circle:
Circumference = 2 $\pi$ × radius
2 × radius = diameter
Circumference = $\pi$ × diameter

We are given:
Circumference = 94

Apply the formula:
94 = $\pi$ d

Divide by $\pi$ on either side to isolate d and find its value

$\frac{94}{ \pi } = \frac{ \pi d}{ \pi }$
$\frac{94}{ \pi } = d$

d ≈ 29.9 cm → Your answer

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The coordinates of the vertices for rectangle ABCD are A (2,4), B (6,10), C (9,8) and D (5,2). What

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Step-by-step explanation:

The computation of the length of a diagonal (AC or BD) of the rectangle is shown below:

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Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4

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$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: x = 3$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: log_{2}(x - 1) log_{2}(x + 5) = 4$

$\qquad \tt \rightarrow \: log_{2} \{(x - 1)(x + 5) \} = 4$

[ log (x) + log (y) = log (xy) ]

$\qquad \tt \rightarrow \: ( x - 1)(x + 5) = {2}^{4}$

$\qquad \tt \rightarrow \: {x}^{2} + 5x - x - 5 = 16$

$\qquad \tt \rightarrow \: {x}^{2} + 4x - 5 - 16 = 0$

$\qquad \tt \rightarrow \: {x}^{2} + 4x -21 = 0$

$\qquad \tt \rightarrow \: {x}^{2} + 7x - 3x - 21 = 0$

$\qquad \tt \rightarrow \: x(x + 7) - 3(x + 7) = 0$

$\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0$

$\qquad \tt \rightarrow \: x = - 7 \: \: or \: \: x = 3$

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

$\qquad \tt \rightarrow \: x = 3$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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2 years ago