Equal to, greater than, or less than?

nalin [4]

=(3)(x)+(3)(4)+(2)(5x)+(2)(2)
=3x+12+10x+4
=3x+12+10x+4
=(3x+10x)+(12+4)
=13x+16

Answer = 13x+16
(hope this helps)

4 0

2 years ago

Factor. 22 – 7x - 30

polet [3.4K]

-8 - 7x is the factored version.

7 0

2 years ago

Read 2 more answers

Find the midpoint of AC if A is located at (-4,9) and C is located at (1,31)

aliina [53]

The midpoint of AC is (-1.5, 20)

3 0

2 years ago

A phone company offers two monthly plans. Plan A costs

Rus_ich [418]

For plan A it will only take five minutes to amount to $20.50

Plan B will need 30 min to cost the same as plan A $20.50

3 0

3 years ago

Read 2 more answers

8 freshmen, 9 sophomores, 9 juniors, and 7 seniors are eligible to be on a committee.

loris [4]

Answer: 11113200

Step-by-step explanation:

We know that , the number of combination of choosing r things from n things is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Then , the number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors :-

$^8C_4\times ^9C_5\times^9C_2\times^7C_3$

$=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200$

∴ The number of ways to choose a dancing committee if it is to consist of 4 freshmen, 5 sophomores, 2 juniors, and 3 seniors = 11113200

6 0

3 years ago