Answer: Tristan can pick them out in 6 different ways
Step-by-step explanation: In the waiting room the four magazines all have an equal chance of being picked first and then others would be picked subsequently. If we are to pick magazine A first of all, then the others would be picked as B, C and D, or C, B and D, or D, B and C, and so on.
However, rather than spend so much time counting the different ways we can apply the mathematical method of permutation. Since choosing the first one means we can’t choose it again but others have to be chosen, and all four magazines each has an equal chance of being chosen first, then the number of all possible permutations is given as 4! (four factorial).
The question requires us to chose three out of the four magazines, so we shall apply 3!.
3! = 3 x 2 x 1
3! = 6
Therefore, there are 6 different ways to pick three out of the four magazines
Expanded- 100000000+10000000+9000000+4
The answer is True.
Explanation:
Let a = major axis
Let b = minor axis
Let c = focal length.
Consider the right focus, located a distance c from the center of the ellipse (at the origin).
From the right focus to the right point on the major axis is equal to a-c. This is the minimum distance.
From the right focus to the left point on the major axis is equal to a+c. This is the maximum distance.
323 because I did the quiz and got it right txt me if you need help
3<9h I hope this helps you
