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kap26 [50]
3 years ago
10

Which graph represents the function y=4

Mathematics
2 answers:
Maksim231197 [3]3 years ago
8 0
A. You can remember which axis is which by Y-axis is the vertical one (Y to the sky) and X- axis is horizontal. it's not C because you don't have a second point. It's not (0,4) it's just 4.
VMariaS [17]3 years ago
4 0

Answer:

The correct answer is A.

Step-by-step explanation:

The function y = 4 is a constant function. This means that his output value is the same for every input value. In other words, the Image of this function remains constant, for all the numbers in his Domain.

In this case y = 4, for x (-∞,∞).

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find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0​
Citrus2011 [14]

Answer:

Radius: r =\frac{\sqrt {21}}{6}

Center = (-\frac{3}{2}, -\frac{2}{3})

Step-by-step explanation:

Given

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Solving (a): The radius of the circle

First, we express the equation as:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

So, we have:

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Divide through by 9

x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0

Rewrite as:

x^2  + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}

Group the expression into 2

[x^2  + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

Next, we complete the square on each group.

For [x^2  + 3x]

1: Divide the coefficient\ of\ x\ by\ 2

2: Take the square\ of\ the\ division

3: Add this square\ to\ both\ sides\ of\ the\ equation.

So, we have:

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

[x^2  + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Factorize

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Apply the same to y

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}

Add the fractions

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

Recall that:

(x - h)^2 + (y - k)^2 = r^2

By comparison:

r^2 =\frac{7}{12}

Take square roots of both sides

r =\sqrt{\frac{7}{12}}

Split

r =\frac{\sqrt 7}{\sqrt 12}

Rationalize

r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}

r =\frac{\sqrt {84}}{12}

r =\frac{\sqrt {4*21}}{12}

r =\frac{2\sqrt {21}}{12}

r =\frac{\sqrt {21}}{6}

Solving (b): The center

Recall that:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

From:

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

-h = \frac{3}{2} and -k = \frac{2}{3}

Solve for h and k

h = -\frac{3}{2} and k = -\frac{2}{3}

Hence, the center is:

Center = (-\frac{3}{2}, -\frac{2}{3})

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3 years ago
Cd is 1/20 inch thick if you have 52 CD's what is the height of the stack
Karo-lina-s [1.5K]
To get the answer you divide the cds by 2 because the CD's are 1/2 in thick to get: 26 in
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The function d(s) = 0.0056s squared + 0.14s models the stopping distance
victus00 [196]

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be d(s) = 0.0056\cdot s^{2} + 0.14\cdot s, where d is the stopping distance measured in metres and s is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of d(s).

2) Add the function d = 7\,m.

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

4 0
3 years ago
Victoria wants to plant a vegetable garden in the shape of a square. she has a space allocated in her backyard that will accommo
Nastasia [14]

The side is (2x+3)?  then the area is: (2x+3)(2x+3) = 4 x^2 + 12 x + 9  if x = 6 then Area = 4(36)+12(6)+9 = 144 + 72 + 9 = 225, too big :(

8 0
3 years ago
How does a digit in the ten thousands place compare to a digit in the thousands place?
svetlana [45]
The digits in the ten-thousands place is 10,000 times the value of a digit, right? For example, 10,000 is 10,000 times 1, and one is a mere digit. The thousands place follows the same rule, with 1,000 being 1,000 times 1. Ergo, when compared, you could think of it as 10,000/1,000 = 10. We can think of this as a digit in the ten-thousands place is 10 times the value of the same digit in the thousands place.
8 0
3 years ago
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