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kap26 [50]
3 years ago
10

Which graph represents the function y=4

Mathematics
2 answers:
Maksim231197 [3]3 years ago
8 0
A. You can remember which axis is which by Y-axis is the vertical one (Y to the sky) and X- axis is horizontal. it's not C because you don't have a second point. It's not (0,4) it's just 4.
VMariaS [17]3 years ago
4 0

Answer:

The correct answer is A.

Step-by-step explanation:

The function y = 4 is a constant function. This means that his output value is the same for every input value. In other words, the Image of this function remains constant, for all the numbers in his Domain.

In this case y = 4, for x (-∞,∞).

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A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
4 years ago
Solve the system algebraically. Check your work.
Luden [163]

answer.

Answer:

x=2 and y=0 is the required result.

Step-by-step explanation:

We have been given system of equations:

5x+2y=105x+2y=10     (1)

And 3x+2y=63x+2y=6      (2)

We will use elimination method:

Multiply 1st equation by 3 and 2nd equation by 5 we get:

15x+6y=3015x+6y=30      (3)

15x+10y=3015x+10y=30      (4)

Now subtract  (4) from (3) we get:

-4y=0−4y=0

y=0y=0

Now, put y=0 in (1) equation:

5x+2(0)=105x+2(0)=10

5x=105x=10

x=2x=2

Hence, x=2 and y=0

8 0
4 years ago
Kathy had a dream in which she was selling roses in an international market. She started out with 156 roses. Then her first cust
KengaRu [80]

Answer: 170

Step-by-step explanation:

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3 years ago
Which is NOT a function? <br> A y – x = 6<br> B y = 2x<br> C x = -2<br> D y + x = 12
Fantom [35]

Answer:

D

Step-by-step explanation:

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3 years ago
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