Step-by-step explanation:
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1. Answer: To create graphs from verbal expressions, first you have to write the verbal expression as a function. Then, you can create a table of values to look for a pattern and graph the function. The key features of any function can be compared in tables and graphs by creating the matching graph for the function.
2. It is because there is no value of x that will cause the value of f(x) in the formula to equal 0. Notice that the graph crosses the y-axis at 1. ... The inverse of an exponential function is a logarithmic function and the inverse of a logarithmic function is an exponential function
3. y = e^x is an exponential function that increases gradually from (-∞, 0) until it reaches the point (0,1). Thereafter, it very sharply increases on (0,∞).
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Answer:
The third option, y=(-1/3)x-7
Step-by-step explanation:
To find a line perpendicular to an equation, you find the negative reciprocal of the slope. For instance, if you have an equation y=4x+5, the negative reciprocal is y=(-1/4)x+5. That is the equation to find a line perpendicular to this.
If you want to find a line parallel to the equation y=4x+5, all you have to do is come up with another equation that has the same slope. So, y=4x+8 would be a line parallel to the equation y=4x+5.
The answer is -7.20 click on file for more details.
Answer:
A| 12, 3
Step-by-step explanation:
The polynomial can be factored by looking for factors of 36 that sum to -15. The sum being negative while the product is positive means both factors will be negative. The answer choices suggest ...
y = (x -12)(x -3)
A quick check shows this product is ...
y = x^2 -12x -3x +36 = x^2 -15x +36 . . . . as required
The factors are zero when x is either 12 or 3.
The zeros of the equation are 12 and 3.
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Once you realize the constants in the binomial factors both have a negative sign, you can immediately choose the correct answer (A).
Or, you can use Descartes' rule of signs, which tells you that the two sign changes in the coefficients (+-+) mean there are 2 positive real roots.