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Vera_Pavlovna [14]
2 years ago
14

Help pleaseeeeee I don't understand stand this

Mathematics
1 answer:
likoan [24]2 years ago
3 0

Answer:

the first one is 19-11

Step-by-step explanation:

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Please help!!!! Will mark Brainliest!!!! Pleaseeee!! 20 Points!!!!
Lesechka [4]
Your answer : is b (the letter b)
4 0
2 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
hoa [83]

Answer: 0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8


Step-by-step explanation:

We know that the standard quadratic equation is  ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

b^2-4ac=(-7)^2-4(2)(-9)=49+72>0

So it has 2 real number solutions.

2. a=1, b=-4, c=4

b^2-4ac=(-4)^2-4(1)(4)=16-16=0

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0

So it has 2 real number solutions.

5. a=3, b=5, c=3

b^2-4ac=(5)^2-4(3)(3)=25-36=-9

Thus it does not has real solutions.



5 0
3 years ago
Read 2 more answers
Two numbers total 86 and have a difference of 12. Find the two numbers.
mestny [16]
Let the two numbers be x and y.

x + y = 86
+
x - y = 12
_________
2x + 0 = 98
__________


2x = 98

x = 98/2
 
x = 49


From    x + y = 86

49 + y = 86

y = 86 - 49

y = 37

The numbers are 49 and 37.
4 0
3 years ago
8m^2+ 40m<br> -------------------<br> 8m
dsp73

Answer:

(m+5)

Step-by-step explanation:

Take out 8m as a factor from the top side of the equation. You are left with \frac{8m(m+5)}{8m}  = m+5

6 0
3 years ago
Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f
Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

P(A) = 0.1*0.8 + 0.25*0.2 = 0.13

Probability that a student is foreign and undergraduate:

10% of 80%. So

P(A \cap B) = 0.1*0.8 = 0.08

What is the probability that the student is an undergraduate?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154

0.6154 = 61.54% probability that the student is an undergraduate

8 0
3 years ago
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