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2 years ago

Help pleaseeeeee I don't understand stand this

Mathematics

1 answer:

likoan [24]2 years ago

3 0

Answer:

the first one is 19-11

Step-by-step explanation:

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Please help!!!! Will mark Brainliest!!!! Pleaseeee!! 20 Points!!!!

Lesechka [4]

Your answer : is b (the letter b)

4 0

2 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

3 years ago

Read 2 more answers

Two numbers total 86 and have a difference of 12. Find the two numbers.

mestny [16]

Let the two numbers be x and y.

x + y = 86
+
x - y = 12
_________
2x + 0 = 98
__________

2x = 98

x = 98/2

x = 49

From x + y = 86

49 + y = 86

y = 86 - 49

y = 37

The numbers are 49 and 37.

4 0

3 years ago

8m^2+ 40m<br> -------------------<br> 8m

dsp73

Answer:

$(m+5)$

Step-by-step explanation:

Take out 8m as a factor from the top side of the equation. You are left with $\frac{8m(m+5)}{8m} = m+5$

6 0

3 years ago

Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f

Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

$P(A) = 0.1*0.8 + 0.25*0.2 = 0.13$

Probability that a student is foreign and undergraduate:

10% of 80%. So

$P(A \cap B) = 0.1*0.8 = 0.08$

What is the probability that the student is an undergraduate?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154$

0.6154 = 61.54% probability that the student is an undergraduate

8 0

3 years ago