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3 years ago

Joslyn wants to buy 4 packs of pens for 12$ each and a pack of pencils for 6$ how much money does she need

2 answers:

6 0

If one pack of pens costs $12, then 4 packs of pens must cost 12×4 dollars, which is 48

4 packs of pens that cost $12 each is $48 for ONLY the pens.

If she also wants one pack of pencils that costs $6, then take the cost of the pens and add $6

$48+$6 is $54.

Joslyn needs $54 to buy the pens and pencils

user100 [1]3 years ago

5 0

4*12=48
6*1=6

48+6=54

She would need $54

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¿cuáles son los criterios de congruencia y semejanza de triángulo?

mars1129 [50]

Answer:

Two triangles are similar if they meet one of the following criteria. : Two pairs of corresponding angles are equal. : Three pairs of corresponding sides are proportional. : Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

Dos triángulos son similares si cumplen uno de los siguientes criterios. : Dos pares de ángulos correspondientes son iguales. : Tres pares de lados correspondientes son proporcionales. : Dos pares de lados correspondientes son proporcionales y los ángulos correspondientes entre ellos son iguales.

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the value of "?" if the Perimeter = 50 km?

777dan777 [17]

Answer:

14km

Explanation

11km + 11km = 22km is the sum of both the width.

If you want to find the length than minus the perimeter with 22.

50km - 22km = 28km is the sum of both the length.

To know only one side of the length, divide it by 2.

28km/2 = 14km is the length

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3 years ago

If one side of a right triangle is 12 feet long and the hypotenuse of the triangle is 7, find the length of the other side of th

Andreas93 [3]

Answer:

9.74 feet

Step-by-step explanation:

the formula for finding a hypotenuse is $a^{2} + b^{2} = c^{2}$ . We can rearrange that to get: $c^2 - b^2 = a^2$ . So: 49 + b^2 = 144. We get the square root of 95, AKA around 9.74.

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4 years ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

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3 years ago

i am doing integers and the question is Michael withdrew$60 from his checking account name the integer that represent the situat

Slav-nsk [51]

X-60 WITH X BEING THE BANK ACCOUNT TOTAL - THE WITHDRAWAL DO U HAVE ANY ANSWER CHOICES?

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3 years ago