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2 years ago

What is the equation form of the line that is parallel to the line y=-1/3x+4 and passes through the point (6,5)

Mathematics

1 answer:

andriy [413]2 years ago

8 0

Answer: 4

Step-by-step explanation: bc

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The monthly cost in dollars of a long distance phone plan is a linear function of the total calling time in minutes. The monthly

Deffense [45]

Answer:

The monthly cost for 45 minutes is $18.42

Step-by-step explanation:

Let

x -----> the total calling time in minutes

y ----> the monthly cost in dollars

we have the ordered pairs

(42,18.15) and (90,22.47)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{22.47-18.15}{90-42}$

$m=\frac{4.32}{48}$

$m=\$0.09\ per\ minute$

step 2

Find the linear equation in point slope form

$y-y1=m(x-x1)$

we have

$m=0.09\\(x1,y1)=(42,18.15)$

substitute

$y-18.15=0.09(x-42)$

step 3

Find the monthly cost for 45 minutes of calls

For x=45 min

substitute the value of x in the linear equation and solve for y

$y-18.15=0.09(45-42)$

$y-18.15=0.09(3)$

$y-18.15=0.27$

$y=0.27+18.15$

$y=18.42$

therefore

The monthly cost for 45 minutes is $18.42

3 0

3 years ago

Can I please get helped with this I will make you Brainly

Ray Of Light [21]

I’m not sure how technical it’s asking you to be, but
1. Alkali Metals
2. Alkaline earth metals
3. Transition metals
4. Post Transition metals
5. Metalloids
6. Reactive non metals
7. Reactive non metals again
8. Noble gasses
9. Lanthanoids
10. Actinoids

I hope this helps :)

3 0

2 years ago

Anyone know this geometry question?

stiv31 [10]

If D is the midpoint of CE, then CD must be equal to DE

Answer: C

8 0

3 years ago

Explain in detail how to find the vertex: <br> y=-2x^2 + 2x + 3

Cerrena [4.2K]

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-2}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{+3} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)$

$\bf \left(-\cfrac{2}{2(-2)}~~,~~3-\cfrac{2^2}{4(-2)} \right)\implies \left( \cfrac{1}{2}~~,~~3+\cfrac{4}{8} \right)\implies \left(\cfrac{1}{2}~~,~~\cfrac{28}{8} \right) \\\\\\ \left(\cfrac{1}{2}~~,~~\cfrac{7}{2} \right)\implies \left(\frac{1}{2}~,~3\frac{1}{2} \right)$