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3 years ago

Use the table to identify values of p and q that can be used to factor

Mathematics

1 answer:

liberstina [14]3 years ago

3 0

It would be C. -2 and 6

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The probability that a randomly selected elementary or secondary school teacher from a city is a female is , holds a second job

julsineya [31]

Answer:

The probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an elementary or secondary school teacher from a city is a female

<em>Y</em> = an elementary or secondary school teacher holds a second job

The information provided is:

P (X) = 0.66

P (Y) = 0.46

P (X ∩ Y) = 0.22

The addition rule of probability is:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Use this formula to compute the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job as follows:

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.46+0.66-0.22\\=0.90$

Thus, the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.

4 0

4 years ago

Solve using the quadratic formula:20\x+10\(x-10)=10\3

Masja [62]

Answer : x= 15 , 4

steps by step solution : plz see in attachment ✌

Thanks

5 0

3 years ago

. Compute the required sample size given the required confidence in the sample results is 99.74% (Z score of 3). The level of al

Shtirlitz [24]

Answer:

900 sample size

Step-by-step explanation:

To determine the sample size for a proportion, the margin of error formula is used to determine this:

$E=Z_{\frac{\alpha}{2} }*\sqrt{\frac{\hat p \hat q}{{n} }$

$n=\hat p \hat q*(\frac{Z_{\frac{\alpha}{2} }}{E} )^2$

Where p is the proportion, E is the margin of error, n is the sample size, q = 1 - p, $Z_\frac{\alpha }{2}$ is the z score.

Since the proportion is not known, the sample size needed to guarantee the confidence interval and error is at p = 0.5 and q = 1 - p = 1 - 0.5 = 0.5

E = 5% = 0.05, $Z_\frac{\alpha }{2}$ = 3. Hence:

$n=0.5*0.5*(\frac{3}{0.05} )^2\\\\n = 900$

6 0

3 years ago

Plls help im failing

allsm [11]

Answer:

9^35

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

If 5 potatoes together have a mass of 1 kilogram and 8 pears together have a mass of 1200 grams, which has the greater mass, a p

lord [1]

The Potato has more mass

7 0

3 years ago