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iogann1982 [59]
3 years ago
5

Use the table to identify values of p and q that can be used to factor

Mathematics
1 answer:
liberstina [14]3 years ago
3 0
It would be C. -2 and 6
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What is the radius of sphere with a surface area of 100cm2
Novosadov [1.4K]

Answer:

10cm2

Step-by-step explanation:

5 0
3 years ago
How many more equal angles does a square have than a rectangle?
leva [86]
A rectangle, is a quadrilateral with all angles at 90°.

a square is a quadrilateral with all equal sides, and right-angles all around.

now, the rectangle as well as the square, have all right-angles, the only difference is that the square has all equal-length sides, whilst a rectangle can have pairs of sides that vary in length.
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3 years ago
3. Solve the system using
anzhelika [568]

Answer:

D. Infinite solutions.

Step-by-step explanation:

Since they give us the equation for (y) we just implement that equation in place of (y) in the second equation

15x+3y=27 now becomes

15x+3(-5x+9)=27

Distribute the 3

15x-15x+27=27

15x and -15x cancel out

27=27

Infinite solutions since both sides are exactly equal.

Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!

3 0
3 years ago
What is the fraction of 0.344
Genrish500 [490]
Hello!

\bf Answer:

\boxed{ \bf 0.334~=~344/100~or~43/125} as a fraction.

0.344 = 0.344/1

The 4 is in the thousandths place. Multiply both the numerator and the denominator by 1000.

0.344 × 1000 = 344

1 × 1000 = 1000

This gives us: 344/1000

It's fraction form can be reduced. Simply divide both the numerator and the denominator by 8:

344 ÷ 8 = 43

1000 ÷ 8 = 125

6 0
3 years ago
A game designer must decide how to color five buildings that are in a row. Using only the colors yellow, green, red, and blue, e
earnstyle [38]

Answer:

The total of ways the buildings can be painted are  = 4 \times 3  \times 2  \times 2  \times 1 = 48 ways.

Step-by-step explanation:

i) color five buildings that are in a row.

ii) any two neighboring buildings must be different colors

iii) the first third and fifth buildings must be different colors.

iv) the number of ways to paint the fist building are 4.

v) the number of ways to paint the second building are 3.

vi) the number of ways to paint the third building are 2.

vii) the number of ways to paint the fourth building are 2.

viii) the number of ways to paint the last building are 1.

ix) therefore the total of ways the buildings can be painted are

   = 4 \times 3  \times 2  \times 2  \times 1 = 48 ways.

4 0
3 years ago
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