Answer:
93
<u>Step-by-step:</u>
86 + 7 = 93
<u>The 24 denominator stays the same and just add the numerators:</u>
+
= 93
*also 14 + 13 does not equal 24, its just closest to one of the choices*
Hi, can someone help me with this word problem... i struggle with word problems and can seem to figure this one out!
1 answer:
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Answer:
The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.
Step-by-step explanation:
To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.
Both heads and tails have an individual probability p=0.5.
Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.
The probability that k heads are in the sample is:
Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:
For the last five tosses, the probability that are exactly 4 heads is:
Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:
<h2>Answer:</h2>
<h2>Step-by-step explanation:</h2>
<em>I hope this helps you</em>
<em>:)</em>