Answer:
New mean=71.32
Step-by-step explanation:
The expression for the total initial score is;
T=M×S
where;
T=total initial score
M=mean score
S=number in the set
replacing;
T=unknown
M=72
S=17
replacing;
T=72×17=1,224
The total initial score=1,224
Determine the total score by;
total score=total initial score+total final score
where;
total initial score=1,224
total final score=(68+63)=131
replacing;
total score=1,224+131=1,355
Determine the new mean;
New mean=total score/new number
where;
total score=1,355
new number=(17+2)=19
replacing;
new mean=1,355/19=71.32
Answer:
y= -5
Step-by-step explanation:
x=0 is a vertical graph hence the perpendicular graph would be a horizontal line, a y= ____ graph.
Since it passes through the point (-2, -5),
the equation of the line is y= -5.
This would be in slope- intercept form since the gradient of horizontal lines is zero.
y= mx +c, where m is the gradient and c is the y-intercept.
Given that gradient =0, m=0
y= 0x +c
when x= -2, y= -5,
-5= 0(-2) +c
-5= c
c= -5
Thus the equation is y= -5.
Approximately there are some of these on the we
Ford Family consists of:
a) 2 adults
The price of ticket for each adult is $18.55. This can be approximated to $19 if we round it to nearest dollar. So the price of ticket for 2 adults will be 2 x 19 = $38
b) 3 children between ages 2 and 10.
Ticket for each child between ages 2 - 10 is $12.59 which can be approximated to $13. So ticket price for 3 children will be 3 x 13 = $39
c) 2 children below the age of 2.
Ticket price for each child is $6.54 which can approximated as $7. So ticket price for 2 children will be 2 x 7 = $14
The estimated total amount due on the family equals = 38 + 39 + 14 = $91
In each of the 3 cases we rounded up the values. So this means the actual amount must be slightly lesser than $91. The actual bill was $87.95 which is close to $91 and lesser than it. Hence we can conclude that $87.95 is the correct amount due for Ford Family.
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Answer with explanation:</h2>
Given : A standardized exam's scores are normally distributed.
Mean test score :
Standard deviation :
Let x be the random variable that represents the scores of students .
z-score :
We know that generally , z-scores lower than -1.96 or higher than 1.96 are considered unusual .
For x= 1900
Since it lies between -1.96 and 1.96 , thus it is not unusual.
For x= 1240
Since it lies between -1.96 and 1.96 , thus it is not unusual.
For x= 2190
Since it is greater than 1.96 , thus it is unusual.
For x= 1240
Since it lies between -1.96 and 1.96 , thus it is not unusual.