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ZanzabumX [31]
3 years ago
8

A mayoral candidate would like to know her residents’ views on a public open space before the mayoral debates. She asks only the

people in her office. Her co-workers are an example of a ______.
census
population
convenience sample
simple random sample
Mathematics
2 answers:
Paraphin [41]3 years ago
7 0

Answer:

convenience sample

Step-by-step explanation:


Gala2k [10]3 years ago
7 0

Answer: Convenience Sample

Step-by-step explanation: Biased sample–Parts of the population are favored over others. She only asked people in her office

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What is an equation that passes through (18,2) and is parallel to 3y-x=-12
MrRa [10]
3(2)-18=-12
6-18 = -12
-12 = -12
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3 years ago
Is the following relation a function?<br><br> x y<br> 1 −2<br> 1 −3<br> 2 1<br> 3 −2
vagabundo [1.1K]

Answer:

It is not a function!

Step-by-step explanation:

It is not a function!

A function can't have two y-values assigned to the same x-value. In this case, you can se that for x=1 we have two y-values, which are y= -2 and y= -3.

We can have have two x-values assigned to the same y-value, that's why it's okay that for x=1 and x=3 we have the same y-value y=-2

7 0
3 years ago
PLEASE HELP. i need to show my work for<br> the correct answer. please help
e-lub [12.9K]

Answer:

I THINK IM WRONG BUT

Step-by-step explanation:

X3 NUZZELS POINCES ON U

7 0
2 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
2 years ago
Find the slope using the following two points:<br> (2,-7) and (-1,6)
Advocard [28]

Answer:

13/-3

Step-by-step explanation:

Y2-Y1/X2-X1

7 0
3 years ago
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