Using the speed - distance relationship, the time left before the appointed time is 27 minutes.
<u>Recall</u><u> </u><u>:</u>
<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>
- Distance = 10 × (t + 3) = 10t + 30 - - - (1)
<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>
- Distance = 12 × (t - 2) = 12t - 24 - - - - (2)
<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>
10t + 30 = 12t - 24
<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>
10t - 12t = - 24 - 30
-2t = - 54
<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>
t = 54 / 2
t = 27
Hence, the time left before the appointed time is 27 minutes.
Learn more : brainly.com/question/25669152
The answer actually is 4,245 BUT that is the correct way to do it because you take the smaller population away from the larger population in order to find their difference in sizes.
Answer:
3x-4y-6x+28y
-3x-6x-4y+28y
-9x+24y
Step-by-step explanation:
In order to make

a mixed number you have to do division.

. Check:

. Therefore,

as a mixed number is

. Hoped I helped. :)
Answer:
(1.2, –4.7)
Step-by-step explanation:
Since in the question it is mentioned that on the plane of coordinate, a line is made from point A (7,-2) to point B(-8,-9)
Also, the ratio of A to B is 5:8
Based on this, the x and y coordinates at point C is
![= [\frac{5\times (-8) + 8\times 7}{5 + 8} , \frac{5\times (-9) + 8\times -2}{5 + 8}]\\\\= [\frac{16}{3}, \frac{-61}{13}]](https://tex.z-dn.net/?f=%3D%20%5B%5Cfrac%7B5%5Ctimes%20%28-8%29%20%2B%208%5Ctimes%207%7D%7B5%20%2B%208%7D%20%2C%20%5Cfrac%7B5%5Ctimes%20%28-9%29%20%2B%208%5Ctimes%20-2%7D%7B5%20%2B%208%7D%5D%5C%5C%5C%5C%3D%20%5B%5Cfrac%7B16%7D%7B3%7D%2C%20%5Cfrac%7B-61%7D%7B13%7D%5D)
= (1.2, –4.7)
Hence, the x and y coordinates of point C is (1.2, –4.7)
Therefore the last option is correct