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3 years ago

12

PLEASE ANSWER QUICK!!!

1 answer:

aivan3 [116]3 years ago

6 0

Answer:

(0,5) and (1,0)

Step-by-step explanation:

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Find the volume of the solid formed by revolving the region bounded by LaTeX: y = \sqrt{x} y = x and the lines LaTeX: y = 1 y =

Strike441 [17]

Answer:

The volume is:

$\displaystyle\frac{37\pi}{10}$

Step-by-step explanation:

See the sketch of the region in the attached graph.

We set the integral using washer method:

$\displaystyle\int_a^b\pi r^2dx$

Notice here the radius of the washer is the difference of the given curves:

$x-\sqrt{x}$

So the integral becomes:

$\displaystyle\int_1^4\pi(x-\sqrt{x})^2dx$

We solve it:

Factor $\pi$ out and distribute the exponent (you can use FOIL):

$\displaystyle\pi\int_1^4x^2-2x\sqrt{x}+x\,dx$

Notice: $x\sqrt{x}=x\cdot x^{1/2}=x^{3/2}$

So the integral becomes:

$\displaystyle\pi\int_1^4x^2-2x^{3/2}+x\,dx$

Then using the basic rule to evaluate the integral:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{2x^{5/2}}{5/2}+\frac{x^2}{2}\right|_1^4$

Simplifying a bit:

$\displaystyle\pi\left[\frac{x^3}{3}-\frac{4x^{5/2}}{5}+\frac{x^2}{2}\right|_1^4$

Then plugging the limits of the integral:

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Taking the root (rational exponents):

$\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]$

Then doing those arithmetic computations we get:

$\displaystyle\frac{37\pi}{10}$

6 0

3 years ago

Is the data set "distance a baseball travels after being hit" quantitative or qualitative? If it is quantitative, is it discrete

Komok [63]

<span>quantitative, continuous</span>

8 0

4 years ago

Read 2 more answers

Calculate the length b to two decimal places.

Andrej [43]

Answer:

B. 21.64

Step-by-step explanation:

We have been given a triangle and we are asked to find the length of AC (b).

We will use law of cosines to find the length of side AC.

$c^{2}=a^{2}+b^{2}-2ab \text{ cos }\theta$

Upon substituting our given values in the formula we will get,

$(AC)^{2}=15^{2}+12^{2}-2\times 15\times 12 \text{ cos}(106)$

$(AC)^{2}=225+144-360\text{ cos}(106)$

$(AC)^{2}=369-360(-0.275637355817)$

$(AC)^{2}=369+99.22944809412$

$(AC)^{2}=468.22944809412$

Upon taking square root of both sides of our equation we will be get,

$AC=\sqrt{468.22944809412}$

$AC=21.6386101238993629\approx 21.64$

Therefore, the length of b is 21.64 and option B is the correct choice.

6 0

3 years ago

Find the value of x so that the figures have the same area.<br><br> 25ft, x-6 ft<br><br> x ft, 15ft

levacccp [35]

X=11ft
25-6=14
So ur answer is actually 3

3 0

4 years ago

F(x)=x² <br> G(x)=(x-6)²<br> Complete the description of the transformation

artcher [175]

6 units to the right

5 0

3 years ago

Read 2 more answers