We know that standard form = the number that is not expanded.
This equation is expanded so standard form =
2*100=200
9*10=90
6*1=6
3*1/10= 0.3
8*1/100=0.08
200+90=290
290+6=296
296+0.3=296.3
296.3+0.08=296.38
Your answer is 296.38
Hope this helped!
The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
<h2><u>Solution (1)</u> :</h2>
Given, to find A we have to :
- square m
- Add y to m²
- Subtract 7 from m² + y
From the question, the following equation can be formed :

Therefore, the formula for finding A = m² + y - 7
<h2><u>Solution (2)</u> :</h2>
The value of A we can derive from the formula is :

Value of m = 3 (given)
Which means :




Thus, the value of A = 2+y
Therefore, the value of A = <u>2+y</u>
Answer:
the difference is 25
Step-by-step explanation:
to get from 10 to 0 is 10 units and from 0 to -15 is 15
10+15 = 25
Answer:
an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).