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3 years ago

3. In order to have velocity what is needed? 4. What is an example of acceleration?

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

Answer: Velocity needs both magnitude and direction

Step-by-step explanation:

Velocity is defined as a Vector quantity which implies that one needs to know both the magnitude and the direction of the object, as a reference frame. The expression for velocity is defined as:

Velocity = Distance * Time <=> V= dt

Acceleration occurs when an object initially moving with a constant velocity, changes motion and velocity increases with time. The expression for acceleration is defined as:

Acceleration = Velocity * Time <=> A= Vt

A typical example of acceleration is a Free Falling Object (i.e. letting a ball drop from a building)

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The answer is 36

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The water level in a lake was monitored and was noted to have changed -2 1/3 inches in one year. The next year it was noted to h

Diano4ka-milaya [45]

Answer:

The total change in water level over the past 2 years is $\displaystyle -4 \frac{1}{6}$ .

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Fractions

Proper and Improper

Numbers

Least Common Multiple (LCM)

Step-by-step explanation:

Step 1: Define

Identify

Year 1 water change: $\displaystyle -2 \frac{1}{3}$

Year 2 water change: $\displaystyle -1 \frac{5}{6}$

Step 2: Find Total Water Change

[Set up] Add yearly water changes: $\displaystyle -2 \frac{1}{3} + -1 \frac{5}{6}$
[Fractions] Convert to improper: $\displaystyle \frac{-7}{3} - \frac{11}{6}$
[Fraction] Rewrite [LCM]: $\displaystyle \frac{-14}{6} - \frac{11}{6}$
[Order of Operations] Subtract: $\displaystyle \frac{-25}{6}$
[Fraction] Convert to proper: $\displaystyle -4 \frac{1}{6}$

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2 years ago

Find the midpoint of the segment with the following endpoints. (6,3) and (2,7) Please help?

BabaBlast [244]

Answer:

(-4,4)

Step-by-step explanation:

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3 years ago

A square grassy field is watered by 4 sprinklers. The sprinklers spray water in a circular pattern, as shown above. If the field

enot [183]

The answer is (3600 - 900π) ft²

Step 1. Find the radius r of circles.
Step 2. Find the area of the portion of the field that will be watered by the sprinklers (A1)
Step 3. Find the total area of the field (A2)
Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A)

Step 1. Find the radius r of circles
r = ?
According to the image, radius of a square is one fourth of the field side length:
r = s/4
s = 60 ft
r = 60/4 = 15 ft

Step 2. Find the area of the portion of the field that will be watered by the sprinklers.
The area of the field that will be watered by the sprinklers (A1) is actually total area of 4 circles with radius 15 ft.
Since the area of a circle is π r², then A1 is:
A1 = 4 * π r² = 4 * π * 15² = 900π ft²

Step 3. Find the total area of the field (A2)
The field is actually a square with side s = 60 ft.
A2 = s² = 60² = 3600 ft²

Step 4. Find the area of the portion of the field that will not be watered by the sprinklers (A).
To get the area of the portion of the field that will not be watered by the sprinklers (A) we need to subtract the area of 4 circles from the total area:
A = A2 - A1
A = (3600 - 900π) ft²

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