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3 years ago

(05.03 MC)

Mathematics

1 answer:

NeTakaya3 years ago

3 0

Answer:

i did this

Step-by-step explanation:

i dont remember though

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Simplify to create an equivalent expression 6(5r-11)-(5-r)

dolphi86 [110]

Answer:

B or 31r-71

Step-by-step explanation:

First, use distributive property to expand the first term.

30r-66-(5-r)

Remove the parenthesis of the third term:

30r-66-5+r

Combine like terms

31r-71

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4 years ago

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Please help ASAP!!! Will give Brainly!!! What are the x-intercepts of the parabola?

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Answer:

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Step-by-step explanation:

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3 years ago

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What is the remainder when 23,870 ÷ 38

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4 years ago

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A manufacturer of electronic kits has found that the mean time required for novices to assemble its new circuit tester is 3 hour

vitfil [10]

Testing the hypothesis using the z-distribution, it is found that since the p-value of the test is of 0.0262 < 0.05, it can be concluded that the new booklet is effective.

At the null hypothesis, we test if there has been no improvement, that is, the time is still of 3 hours. Hence:

$H_0: \mu = 3$

At the alternative hypothesis, we test if there has been improvement, that is, the time is of less than 3 hours. Thus:

$H_1: \mu < 3$

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the population.
n is the sample size.

In this problem, the values of the parameters are: $\mu = 3, \sigma = 0.2, \overline{x} = 2.9, n = 15$ .

Then, the value of the test statistic is:

$z = \frac{2.9 - 3}{\frac{0.2}{\sqrt{15}}}$

$z = -1.94$

The p-value of the test is the probability of finding a sample mean of 2.9 hours or less, which is the p-value of z = -1.94.

Looking at the z-table, z = -1.94 has a p-value of 0.0262.

Since the p-value of the test is of 0.0262 < 0.05, it can be concluded that the new booklet is effective.

A similar problem is given at brainly.com/question/25413422

8 0

3 years ago