Cone details:
Sphere details:
================
From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.
<u>Using Pythagoras Theorem</u>
(a)
TO² + TU² = OU²
(h-10)² + r² = 10² [insert values]
r² = 10² - (h-10)² [change sides]
r² = 100 - (h² -20h + 100) [expand]
r² = 100 - h² + 20h -100 [simplify]
r² = 20h - h² [shown]
r = √20h - h² ["r" in terms of "h"]
(b)
volume of cone = 1/3 * π * r² * h
===========================




To find maximum/minimum, we have to find first derivative.
(c)
<u>First derivative</u>

<u>apply chain rule</u>

<u>Equate the first derivative to zero, that is V'(x) = 0</u>




<u />
<u>maximum volume:</u> <u>when h = 40/3</u>


<u>minimum volume:</u> <u>when h = 0</u>


Answer:
Step-by-step explanation:
Using the exponential growth function for the U. S. population from 1970 through 2003:
A = 205.1e^0.011t
with the U.S. population being 205.1 million in 1970, when would the U. S. population reach 350 million?
A.
2028
B.
2048
C.
2018
D.
2038
We have the expression
A = 205.1e^0.011t
We are asked to find when would the U. S. population reach 350 million
A = 350
350 = 205.1e^0.011t
We divide both sides by 205.1
Divide both sides by 205.1
350/205.1 = 205.1e^0.011t/205.1
1.7064846416 = e^0.011t
We take the log of both sides
log 1.7064846416 = log e^0.011t
log 1.7064846416 = t log 0.011
t = log 1.7064846416/ log 0.011
t = 0.1185057826
Answer:
$19.61
Step-by-step explanation:
To find how much Selena spent, multiply the amount by the price per pound. She spent 5.62 (3.49) = $19.61.
Answer: is 5.2
Step-by-step explanation:
you add 8+1+5+0+12 and you then divide it by 5 and you get 5.2
y = 12x represents the gallons of paint used in x hours.
Step-by-step explanation:
CJ uses 3 gallons of paint in 15 minutes,
15 minutes = 3 gallons
1 minutes = 
1 hour = 60 minutes
Gallons of paint used in 1 hour;
1 hour = 
CJ uses 12 gallons of paint in 1 hour.
For x hours = 12*x = 12x
Gallons of paints used = y
y = 12x represents the gallons of paint used in x hours.
Keywords: linear equation, multiplication
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