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Katena32 [7]
3 years ago
9

Please help it is due tomorrow.

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0
R = radius of basketball
r = radius of tennis ball 
R = 3.6r cube both sides
the ratio of the radii is 1: 3.6
cube both sides to find the ratio of the volumes 
1 : 46.656 ( this many times greater)
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I have 10 min left can I get some help
Yuki888 [10]

Answer:

14

Step-by-step explanation:

6 0
3 years ago
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If f(x) -3 and g(x) = 3x2+x-6, find (f+9)(x).
s2008m [1.1K]

Answer:

3x^2 +x -3

Step-by-step explanation:

f(x)= 3 and g(x) = 3x^2+x-6

f+g (x) =  3+  3x^2+x-6

Combine like terms

          = 3x^2 +x -3

6 0
4 years ago
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In a community fitness group, 40% of members run for exercise and 36% of members run and play a sport. What percentage of member
tiny-mole [99]
Imagine you have 100 people, this means 40 of them run for exercise. We also know 36 people run for exercise AND play a sport. So 36 of the 40 runners are the percentage we are looking for, this would be 36/40=0.9 or 90% 
5 0
3 years ago
Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.
faltersainse [42]
f(x) = \frac{x + 4}{3x^{2} + 5x - 2}

                     3x² + 5x - 2 = 0
                3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
          3x(x + 2) - 1(x + 2) = 0
                  (3x - 1)(x + 2) = 0
3x - 1 = 0       or       x + 2 = 0
    + 1 + 1                     - 2  - 2 
     3x = 1          or          x = -2
      3     3                       1     1
       x = ¹/₃         or         x = -2

      f(x) = 3x² + 5x - 2
     f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
     f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
     f(¹/₃) = ¹/₃ - ¹/₃
     f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)

      f(x) = 3x² + 5x - 2
     f(-2) = 3(-2)² + 5(-2) - 2
     f(-2) = 3(4) - 10 - 2
     f(-2) = 12 - 12
     f(-2) = 0
(x, f(x)) = (-2, 0)

    Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
      Oblique Asymptote: No Asymptotes
3 0
4 years ago
Read 2 more answers
Let f(x)=4^x. The new function g(x)=f(x-1)+3 represents transformations that were made to function f.
Shkiper50 [21]

Answer:

g(x) = 4^{x-1} + 3

Step-by-step explanation:

Given

f(x) = 4^x

g(x) = f(x-1) + 3

Required

Determine g(x)

First, we need to calculate f(x-1)

Given that:

f(x) = 4^x

Subtract 1 from x

f(x-1) = 4^{x-1}

Add 3 to both sides

f(x-1) + 3 = 4^{x-1} + 3

Recall that:

g(x) = f(x-1) + 3

This implies that:

g(x) = 4^{x-1} + 3

4 0
3 years ago
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