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Katena32 [7]
3 years ago
9

Please help it is due tomorrow.

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0
R = radius of basketball
r = radius of tennis ball 
R = 3.6r cube both sides
the ratio of the radii is 1: 3.6
cube both sides to find the ratio of the volumes 
1 : 46.656 ( this many times greater)
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What value of X makes the equation -5x-(-7-4x)=-2(3x-4) true?
rjkz [21]

Answer: x= \frac{1}{5} Makes It True

Explantion: step 1: simplify both sides of the equation. −5x−(−7−4x)=−2(3x−4) −5x+−1(−7−4x)=−2(3x−4)(distribute the negative sign) −5x+(−1)(−7)+−1(−4x)=−2(3x−4) −5x+7+4x=−2(3x−4) −5x+7+4x=(−2)(3x)+(−2)(−4)(distribute) −5x+7+4x=−6x+8 (−5x+4x)+(7)=−6x+8(combine like terms) −x+7=−6x+8 −x+7=−6x+8 step 2: add 6x to both sides. −x+7+6x=−6x+8+6x 5x+7=8 step 3: subtract 7 from both sides. 5x+7−7=8−7 5x=1

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

3 0
3 years ago
Read 2 more answers
Mama dbdjd d did f dbjdbf ddbdnd
Blizzard [7]

Answer:

ah yes mama

Step-by-step explanation:

8 0
3 years ago
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Given that the diameter of Circle A is 6 cm , and the radius of Circle B is 18 cm , what can be concluded about the two circles?
ELEN [110]

Answer:

The radius of circle B is 6 times greater than the radius of circle A

The area of circle B is 36 times greater than the area of circle A

Step-by-step explanation:

we have

<em>Circle A</em>

D=6\ cm

The radius of circle A is

r=6/2=3\ cm -----> the radius is half the diameter

<em>Circle B</em>

r=18\ cm

Compare the radius of both circles

3\ cm< 18\ cm

18=6(3)

The radius of circle B is six times greater than the radius of circle A

Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared

All circles are similar

In this problem the scale factor is 6

so

6^{2}=36

therefore

The area of circle B is 36 times greater than the area of circle A

8 0
3 years ago
1500/semiannual period for 6 years at 2.5%/year compounded semiannually
kari74 [83]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannual, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &6 \end{cases} \\\\\\ A=1500\left(1+\frac{0.025}{2}\right)^{2\cdot 6}\implies A=1500(1.0125)^{12}\implies A\approx 1741.13

6 0
3 years ago
Which are the solutions of the quadratic equation x^2=9x+6
zzz [600]
You can use the quadratic equation to solve this once you have this set equal to zero. The answers would be roughly 9.6 and -0.6. 
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3 years ago
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