All categories

3 years ago

Help! I fallen and can’t get up.

Mathematics

2 answers:

Gnom [1K]3 years ago

7 0

I miss when everyone always said this

good times but ty for the points

katrin2010 [14]3 years ago

3 0

boo hoo let me play you a sad song on the world's smallest violin

You might be interested in

Write the equation in y=mx+b form please????

Solnce55 [7]

ANSWER

$y = - 2x - 5$

EXPLANATION

We can use any two points to determine the slope.

The line passes through;

(-3,1) and (-5,5).

The slope is given by

$m = \frac{y_2-y_1}{x_2-x_1}$

This implies that;

$m = \frac{5 - 1}{ - 5 - - 3}$

$m = \frac{4}{ - 2} = - 2$

We can now find the equation using the formula;

$y-y_1=m(x-x_1)$

$y - 1 = - 2(x + 3)$

Expand:

$y = - 2x -6 + 1$

$y = - 2x - 5$

6 0

3 years ago

Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans

tatyana61 [14]

Answer:

3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

$\dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}$

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

Example:

$\dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}$

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0

2 years ago

Is this set of numbers a Pythagorean triple? yes or no

Kaylis [27]

Answer:- No.

Explanation :-

Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.

Pythagoras theorem :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.

Here,

hypotenuse = 12 (as it is the longest side)

and other two sides are 6 and 9.

----> 6^2 + 9^2 = 12^2

----> 36 + 81 = 144

----> 117 = 144

Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.

8 0

3 years ago

Suppose you have the 26 letters of the alphabet on separate cards in a hat. You pick out a card, write down the letter, put the

tekilochka [14]

The probability is 4/26 since MATH has 4 letters. It might be a trick question though because you're putting the card back in the hat, therefore it might be different. Sorry if this is too confusing I overthink it lol

8 0

3 years ago

PLEASE HELP ASAP 15 POINTS

kobusy [5.1K]

1) m=-2

2) C) y=-3/4x -6

3) D) y=2/5x-2

I don't understand 4 nor 5. My apologies.

6) Parallel

4 0

2 years ago