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Solve for j(h(x)):
h(x) = x² + 4
j(x) = 4x - 1
Substitute in h(x) into "x":
j(h(x)) = 4(x² + 4) - 1
j(h(x)) = 4x² + 16 - 1
j(h(x)) = 4x² + 15
Solve at x = 2:
4(2)² + 15 = 4(4) + 15 = 31.
2.15 X 58 = ? (please do an explanation too)
2 answers:
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The factors of the quadratic equation are (x+3) and (x-15).
<h2 /><h2>Given to us</h2>The factors of .
As we can see in the quadratic equation the value of ac is -45x². therefore, we need to divide -12x into two parts such that their sum must give -12x and their product gives us -45x².
therefore, dividing -12x into -15x and 3x,
Taking common out,
Hence, the factors of the quadratic equation are (x+3) and (x-15).
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