Let q and n represent the number of quarters and nickels respectively.
q=3n and .05n+.25q=1.6 These are the conditions in mathematical terms.
To solve, use the value of q from the first equation in the second equation to get:
.05n+.25(3n)=1.6 carry out indicated multiplication on left side
.05n+.75n=1.6 combine like terms on left side
.8n=1.6 divide both sides by .8
n=2, since q=3n
q=6
So Peggy had 2 nickels and 6 quarters.


for example, let's look at the first set
y+3x =5 or y = -3x+ 5
and y = -3x + 2
y = m + b
the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
80=6th graders
40=5th graders
80+40=120
120/22= 60/11
120/25=24/5
120/30= 4
There are 30 students in each class because he teaches 4 class and 120/30 will give you 4.
So u have to solve for p to do that you must isolate p by moving -6 after the equal sign -5+6=1 and there is the answer: 1 hope this helps!!
By changing the number into a decimal, and then moving the decimal twice to the right.