Answer:
this question answer is 1500cm^3
Answer:

*Note c could be written as a/b
Step-by-step explanation:
-sin(-t - 8 π) + cos(-t - 2 π) + tan(-t - 5 π)
The identities I'm about to apply:



Let's apply the difference identities to all three terms:
![-[\sin(-t)\cos(8\pi)+\cos(-t)\sin(8\pi)]+[\cos(-t)\cos(2\pi)+\sin(-t)\sin(2\pi)]+\frac{\tan(-t)-\tan(5\pi)}{1+\tan(-t)\tan(5\pi)}](https://tex.z-dn.net/?f=-%5B%5Csin%28-t%29%5Ccos%288%5Cpi%29%2B%5Ccos%28-t%29%5Csin%288%5Cpi%29%5D%2B%5B%5Ccos%28-t%29%5Ccos%282%5Cpi%29%2B%5Csin%28-t%29%5Csin%282%5Cpi%29%5D%2B%5Cfrac%7B%5Ctan%28-t%29-%5Ctan%285%5Cpi%29%7D%7B1%2B%5Ctan%28-t%29%5Ctan%285%5Cpi%29%7D)
We are about to use that cos(even*pi) is 1 and sin(even*pi) is 0 so tan(odd*pi)=0:
![-[\sin(-t)(1)+\cos(-t)(0)]+[\cos(-t)(1)+\sin(-t)(0)]+\frac{\tan(-t)-0}{1+\tan(-t)(0)](https://tex.z-dn.net/?f=-%5B%5Csin%28-t%29%281%29%2B%5Ccos%28-t%29%280%29%5D%2B%5B%5Ccos%28-t%29%281%29%2B%5Csin%28-t%29%280%29%5D%2B%5Cfrac%7B%5Ctan%28-t%29-0%7D%7B1%2B%5Ctan%28-t%29%280%29)
Cleaning up the algebra:
![-[\sin(-t)]+[\cos(-t)]+\frac{\tan(-t)}{1}](https://tex.z-dn.net/?f=-%5B%5Csin%28-t%29%5D%2B%5B%5Ccos%28-t%29%5D%2B%5Cfrac%7B%5Ctan%28-t%29%7D%7B1%7D)
Cleaning up more algebra:

Applying that sine and tangent is odd while cosine is even. That is,
sin(-x)=-sin(x) and tan(-x)=-tan(x) while cos(-x)=cos(x):

Making the substitution the problem wanted us to:

Just for fun you could have wrote c as a/b too since tangent=sine/cosine.
Answer:
C. 
Step-by-step explanation:
Because the volume is either 0.15 more or 0.15 less than 21 ounces.
indicate the difference between the volume and 21 and it has to be less than 0.15. Therefore answer C.
It’s D (0,-2) I Saw someone ask this same question!!
Answer:
You should graph the numbers on the side then pin point the coordinates on the graph
Step-by-step explanation: