Since M divides segment AB into a ratio of 5:2, we can say that M is 5/(5+2) of the length of AB. Therefore 5/7 × AB.
distance of AB = d
5/7×(x2 - x1) for the x and 5/7×(y2 - y1) for the y
5/7×(8 - 1) = 5/7 (7) = 5 for the x
and 5/7×(16 - 2) = 5/7 (14) = 10 for the y
But remember the line AB starts at A (1, 2),
so add 1 to the x: 5+1 = 6
and add 2 to the y: 10+2 = 12
Therefore the point M lies exactly at...
A) (6, 12)
D) 12 would NOT be a possible length for the third side because the sum of the 2 shorter legs should be greater than the longest leg.
You have cards with the letters A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P. Event U is choosing the cards A, B, C
Thepotemich [5.8K]
Answer:
If you are asking how many events use P: 1 event is using the letter P (event W)
Step-by-step explanation:
Why event U cannot be using P: This event is only using the letters A, B, C, and D.
Why event V cannot be using P: This event is only using vowels (A, E, I, O, U)
I think it’s the first one because you mirror ABC from the m-axis and then rotate ABC 90 degrees clockwise from point B’ to get to the position of triangle A”B’C”
