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mr Goodwill [35]
3 years ago
6

F(x)=-2x^2+4x+5 Find the critical numbers

Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

To find critical points, take the first derivative and set it equal to zero:

f(x) = -2x^2 + 4x + 5

f'(x) = -4x + 4

-4x+4 = 0

-4x = -4

x = 1

Critical point at x = 1

Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.

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devlian [24]

Answer:

No because upon subtracting x on both sides you obtain a false equation of 4=8.

The problem:

What are x values that satisfy:

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Step-by-step explanation:

No number can be substituted into x+4=x+8 to make it true.

There is no number that you can find such that when you add 4 to it will give you the same as adding 8 to it.

Also if you subtract x on both sides you obtain the equation 4=8.

4=8 is not true so x+4=x+8 is never true for any x.

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What is the solution set -4.9x +1.3 > 11.1
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Answer:

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Step-by-step explanation:

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