I believe with a simple google search that 99.9
In this question, you are given the NaOH volume but asked for concentration.
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:
OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
Question 1:
Part 1: A rock formed when an already existing rock is subjected to extreme heat and pressure is metamorphic.
Part 2: A rock formed from particles that are deposited and lithified is sedimentary.
Part 3: A rock formed from cooled and hardened magma or lava is igneous.
These are correct. Ironic they are already in the correct order.
~Hope this helps!
Answer:
9.93
Explanation:
Your value for Kw is incorrect. The correct value is 5.48 × 10^-14.
pH + pOH = pKw
3.30 + pOH = -log(5.84 × 10^-14) = 13.23
pOH = 13.23 - 3.30 = 9.93
The pOH of the solution is 9.93.
Answer:
pH = 4
Explanation:
Step 1: Given data
Concentration of H⁺ ions in the solution ([H⁺]): 10⁻⁴ M
Step 2: Calculate the pH of the solution
We will use the definition of pH.
pH = -log [H⁺]
pH = -log 10⁻⁴ M
pH = 4
The pH of the solution is 4. Considering the pH scale, given the pH is lower than 7, the solution is acidic.
