Answer:
0.89kg
Explanation:
Q=mL L=specific latent heat
Q=energy required in J
m=mass in Kg
Q=mL
m=Q/L
m=2000000J/2.25 x 10^6 J kg-1
m=0.89kg
Answer:
5200 ppm
Explanation:
As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.
Given in the question,
Water = 250 ml = 250 g
Lead = 1.30 g
So,
ppm of Lead =
=
= 5200 ppm
So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.
<u>Answer:</u> The temperature increase will be 31.70°C.
<u>Explanation:</u>
To calculate the increase in the temperature of the system, we use the equation:

where,
q = Heat absorbed = 36.5 kJ = 36500J
m = Mass of water = 275 g
c = Specific heat capacity of water = 
= change in temperature = ? °C
Putting values in above equation, we get:

Hence, the temperature increase will be 31.70°C.
Answer:
We need blood cholesterol because our body uses it to build your structure of cell membranes, make hormones like oestrogen, and testosterone, and to help your metabolism work well.
The balanced chemical equation for the combustion of butane is:

Δ
= Σ
Δ
-Σ
Δ
=
=[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]
= -5315 kJ/mol
Calculating the enthalpy of combustion per mole of butane:

Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol
Correct answer: -2657.5 kJ/mol