Weigh them both and there you go
<u>Answer:</u> The amount of carbon dioxide formed in the reaction is 47.48 grams
<u>Explanation:</u>
For the given chemical equation:

To calculate the actual yield of carbon dioxide, we use the equation:

Percentage yield of carbon dioxide = 83 %
Theoretical yield of carbon dioxide = 1.30 moles
Putting values in above equation, we get:

To calculate the number of moles, we use the equation:

Molar mass of carbon dioxide = 44 g/mol
Moles of carbon dioxide = 1.079 moles
Putting values in above equation, we get:

Hence, the amount of carbon dioxide formed in the reaction is 47.48 grams
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Answer:
0.9875 mole O₂
Explanation:
Rxn => H₂ + ¹/₂O₂ => H₂O
from above reaction, 1 mol H₂ requires ¹/₂ mol O₂ then 1.975 mol H₂ requires ¹/₂(1.975 mol)O₂ or 0.9875 mol O₂.