This is a system of equations.
First, you set everything in terms of y.
Take the first equation and move set everything equal to y
y=0+2x
Since it’s 0, you don’t need to put it, so
y=2x works.
Then, you plug y=2x into the bottom equation, for the y.
-7x +3(2x)=2. You do this because now you have the same variable for both and it can be solved easily.
Then you can simplify.
-7x+3x = 2
Then combine like terms.
-4x = 2
Divide by -4 on each side.
x = -1/2
So, now that you have x, you can plug in your x-value back into the top equation.
-2(-1/2) + y = 0
Combine like terms
1+y=0
Get y by itself
y=-1
There you have it!
You can check by plugging in both values to any of the equations. We will use the top one here.
-2(-1/2) + (-1) =0
+1 + -1 = 0
It works!
So,
X= -1/2
Y= -1
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To solve this question, first cross multiply
Let ? = x
4/9 = x/81
4(81) = 9(x)
Simplify.
81 x 4 = 324
324 = 9x
Isolate the x, divide 9 from both sides
324/9 = 9x/9
x = 324/9
x = 36
4/9 = 36/81
36 is your answer
hope this helps!
Answer:
$712.
Step-by-step explanation:
We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.
We will use compound interest formula to solve our given problem.
, where,
A = Final amount,
P = Principal amount,
r = Annual interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.
Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.
Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.
Answer:
AE
Step-by-step explanation:
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