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lisabon 2012 [21]
3 years ago
10

^ 6 m 8 m What is the length of the hypotenuse? C = meters

Mathematics
1 answer:
ikadub [295]3 years ago
5 0

Answer:

formula: a squared + b squared= c squared

6 squared+ 8 squared= c squared

36+64= c squared

100= c squared

Square root both sides

You get 10= c

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Equations of lines in slope intercept form: through (5,3) and (0,2)
frosja888 [35]

Answer:

y=(x/5)+2

Step-by-step explanation:

Slope = rise over run = (3-2)/(5/0) = 1/5

b = y-intercept = 2

4 0
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Find the volume of the pyramid (round to hundreths place) _______ft^3
wlad13 [49]

Answer:

I got 5ft

Step-by-step explanation:

2ft+2ft+1ft=5ft

3 0
3 years ago
Ms. Sloane earns an 8% commission on her total sales. In February, Ms. Sloane's total sales were $29,250. In March, Ms. Sloane's
sweet-ann [11.9K]

Answer:

$278

Step-by-step explanation:

8% of 29,250 = 2340

8% of 32,725 = 2618

2618 - 2340 = 278

she earned $278 dollars more in march than in february.

3 0
3 years ago
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0
4 years ago
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