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I am Lyosha [343]
3 years ago
14

Will someone please help me?

Mathematics
2 answers:
Helen [10]3 years ago
7 0

Answer:

Viruses are 2 times of the bacteria.

Step-by-step explanation:

Given:

Number of viruses = 2\times 10^9

Number of bacteria = 1\times 10^9

We have to found how many times viruses are greater than the bacteria.

To find how many times,we can divide both the numbers to compare its values.

Lets

Numerator = Number of viruses

Denominator = Number of bacteria

Dividing both we have,

⇒ \frac{2\times 10^9}{1\times 10^9}

⇒ 2\times 10^(^9^-^9) ...\frac{ab^x}{cb^y}=\frac{ab^x^-^y}{c}

⇒ 2\times 10^0       ...a^0=1

⇒ 2

So the viruses are 2 times of the bacteria.

trasher [3.6K]3 years ago
6 0

Answer:

The number of viruses was 2 times greater than bacteria.

Step-by-step explanation:

The number of viruses was 2*10^9, and the number of bacteria was 1*10^9.

To find how many times was the virus number greater than the bacteria number,<em> we just divide the virus number by bacteria number:</em>

<em />\frac{ virus\:number }{bacteria\:number} =\frac{2*10^9 }{1*10^9} = 2*\frac{10^9}{10^9} =2<em />

Viruses are 2 times greater.

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