Question

Will someone please help me?

Answer 1

Answer:

Viruses are 2 times of the bacteria.

Step-by-step explanation:

Given:

Number of viruses = $2\times 10^9$

Number of bacteria = $1\times 10^9$

We have to found how many times viruses are greater than the bacteria.

To find how many times,we can divide both the numbers to compare its values.

Lets

Numerator = Number of viruses

Denominator = Number of bacteria

Dividing both we have,

⇒ $\frac{2\times 10^9}{1\times 10^9}$

⇒ $2\times 10^(^9^-^9)$ ...$\frac{ab^x}{cb^y}=\frac{ab^x^-^y}{c}$

⇒ $2\times 10^0$       ...$a^0=1$

⇒ $2$

So the viruses are 2 times of the bacteria.

Answer 2

Answer:

The number of viruses was 2 times greater than bacteria.

Step-by-step explanation:

The number of viruses was $2*10^9$, and the number of bacteria was $1*10^9$.

To find how many times was the virus number greater than the bacteria number, we just divide the virus number by bacteria number:

$\frac{ virus\:number }{bacteria\:number} =\frac{2*10^9 }{1*10^9} = 2*\frac{10^9}{10^9} =2$

Viruses are 2 times greater.