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2 years ago

Evaluate the expression 81÷ (14 − 5) × 2

Mathematics

2 answers:

mixas84 [53]2 years ago

6 0

Answer:

Step-by-step explanation:

since 81 divided by 9 (which is 14-5) is 9

and 9 multiplied by 2 is 18

Naddik [55]2 years ago

4 0

Answer:

See below.

Step-by-step explanation:

81/(14-5)*2

81/9*2

9*2

-hope it helps

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To find the mode, order the numbers lowest to highest and see which number appears the most often.

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How many of the scores from the group that studied in question eight are in one mean absolute deviation of the mean? Which score

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Add all of the numbers and divide them by the number of numbers there are.

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3 years ago

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Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye

slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

37% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.37$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.37*0.63}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.37*0.63}$

$\sqrt{n} = \frac{2.327\sqrt{0.37*0.63}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.37*0.63}}{0.035})^2$

$n = 1030.4$

Rounding up:

A sample size of 1031 is required.

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3 years ago

Your sample size is 10 and your confidence is 90%. What is your t-score?

PilotLPTM [1.2K]

Answer:

if you want a t*-value for a 90% confidence interval when you have 9 degrees of freedom, go to the bottom of the table, find the column for 90%, and intersect it with the row for df = 9. This gives you a t*–value of 1.833 (rounded).

Step-by-step explanation:

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3 years ago