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vampirchik [111]
2 years ago
10

Evaluate the expression 81÷ (14 − 5) × 2

Mathematics
2 answers:
mixas84 [53]2 years ago
6 0

Answer:

18

Step-by-step explanation:

since 81 divided by 9 (which is 14-5) is 9

and 9 multiplied by 2 is 18

Naddik [55]2 years ago
4 0

Answer:

See below.

Step-by-step explanation:

81/(14-5)*2

81/9*2

9*2

18

-hope it helps

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5(b)
viva [34]

If the side length is greater than 11.11 cm then it will not overflow.

Otherwise, it will overflow.

If Joe tips the bucket of water in a cuboid container and the water is not overflowing then the cuboid container must be of volume greater than 1370 cm³.

We find the cube root of 1370 cm³.

\sqrt[3]{1370} \approx11.11

Then the cuboid container should have a side of length greater than 11.11 cm.

Here the statement  "If I tip my bucket of water in the cuboid container, it will never overflow" is correct or wrong based on the information that the container has a side length lesser or greater than 11.11 cm.

If the side length is greater than 11.11 cm then it will not overflow.

Otherwise, it will overflow.

Learn more about volume here-

brainly.com/question/1578538

#SPJ10

7 0
2 years ago
On a coordinate plane, 2 lines intersect at (0, 5). What is the solution of the system of equations? ( , )
Helga [31]

Answer:

(2,1) is the answer to "On a coordinate plane, 2 lines intersect at (2, 0). The system of equations is shown in the graph.

Note: I would appreciate if you give me 5 stars, a thanks, and brainiest :)

6 0
3 years ago
Read 2 more answers
4. Simplify the expression. <br> -3(b – 7)
ruslelena [56]
-3b+21

hope this helps

5 0
3 years ago
Read 2 more answers
The distribution of the baggage weights for passengers using a particular airline has a mean of 19.4 lbs and a standard deviatio
cupoosta [38]
We are to find the probability that the weight of total luggage for a sample of 100 passengers is less than 2100.

The mean weight of the luggage of passengers will be 2100/100 = 21.

So we have to find the probability of the mean weight to be less than 21.

Average weight = u = 19.4
Standard deviation = 5.3

Since we are dealing with a sample of 100. We will use the standard error.

Standard error = \frac{s}{ \sqrt{n} }= \frac{5.3}{ \sqrt{100} }=0.53

Now we have to convert the weight to z-score

z= \frac{x-u}{ \frac{s}{ \sqrt{n} } }
 
z= \frac{21-19.4}{0.53}=3.018

From z table we can find the probability of z being less than 3.018 is 99.87%.

Therefore, the probability that for (a random sample of) 100 passengers, the total luggage weight is less than 2,100 lbs is 99.87%
8 0
4 years ago
Read 2 more answers
Anyone can help me with this?
Luden [163]
I sure its B i might be wrong tho
5 0
3 years ago
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