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Roman55 [17]
2 years ago
5

Linda goes out with her friends. If the bill is 38.50 and they want to leave a 20% tip, how much should the tip be?

Mathematics
1 answer:
Goryan [66]2 years ago
8 0

Answer:

7.70

Step-by-step explanation:

100%-> 38.50

20% ->7.70

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Which decimal is equivalent to 8 9/12 ? A. 8.12 B. 8.75 C. 8.34 D. 8.9
Dmitriy789 [7]
I think that the answer is D
4 0
3 years ago
What is the solution (x,y) to the system of equations below <br><br> x + 9y = 3<br> y= 1/3 x + 7
Alex_Xolod [135]

Let's solve this by substitution.


y is given by the 2nd eqn as y = (1/3)x + 7. Subst. (1/3)x + 7 into the first eqn as a replacement for y: x + 9( (1/3)x + 7) = 3.


clear out fractions by mult. all 3 terms by 3: 3x + 9x + 63 = 3


Combine like terms: 12x = -60. Then x = -5


Find y by subst. -5 for x in the 2nd equation: y = (1/3)(-5) + 7

= -5/3 + 35/3 = 30/3 = 10.


Thus, the solution (x,y) of this system is (-5,10).


4 0
3 years ago
Two cars, A and B, are travelling along a straight road and in the same direction. Car B is 20 km
pishuonlain [190]

Answer:

2 o'clock

Step-by-step explanation:

Their 'closing speed' is 60 - 50 = 10 km/hr

they have 20 km between them

 at closing speed this will take   20 km / 10 km/hr = 2 hours for the cars to meet....this would be at 14:00    or  2 oclock

5 0
2 years ago
Simplify each expression using the proper order of operations. please help thank you so much :)
Tasya [4]

Answer:

\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4

12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}

\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12

7^2 - 5* 8+1 = 10

(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18

Step-by-step explanation:

<em>Required: Solve the expressions using proper operation order</em>

To solve this, we'll make use of BODMAS

--------------------------------------------------------------------------------------------------------

\frac{41 - 3^2}{\sqrt{36} * 3 - 26}

Evaluate all squares and square roots

\frac{41 - 3*3}{\sqrt{36} * 3 - 26}

\frac{41 - 3*3}{6 * 3 - 26}

Evaluate the numerator (Start by multiplying 3 * 3)

\frac{41 - 9}{6 * 3 - 26}

Subtract 9 from 41

\frac{32}{6 * 3 - 26}

Evaluate the denominator (Start by multiplying 6 * 3)

\frac{32}{18 - 26}

\frac{32}{-8}

Divide 32 by -8

-4

Hence;

\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4

--------------------------------------------------------------------------------------------------------

12 + 3\sqrt{8} * (9 - 2)

Start by evaluating the bracket

12 + 3\sqrt{8} * 7

Then evaluate the multiplication

12 + 21\sqrt{8}

Simplify the square root

12 + 21\sqrt{4 * 2}

Split the square root

12 + 21\sqrt{4} * \sqrt{2}

Take Square root of 4

12 + 21 * 2} * \sqrt{2}

12 + 42 \sqrt{2}

Hence;

12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}

--------------------------------------------------------------------------------------------------------

\frac{28 - (7^2 + 3)}{-13 + 3 * 5}

Evaluate 7²

\frac{28 - (49 + 3)}{-13 + 3 * 5}

Evaluate all expression in the bracket

\frac{28 - (52)}{-13 + 3 * 5}

\frac{28 - 52}{-13 + 3 * 5}

Evaluate 3 * 5

\frac{28 - 52}{-13 + 1 5}

\frac{-2 4}{2}

-12

Hence;

\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12

--------------------------------------------------------------------------------------------------------

7^2 - 5* 8+1

Evaluate 7²

49 - 5* 8+1

Evaluate 5 * 8

49 - 40 + 1

10

7^2 - 5* 8+1 = 10

--------------------------------------------------------------------------------------------------------

(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1

Evaluate all square root and cube root

(2 * 4) - (3 * 9) + 1

Solve the expressions in bracket

8 - 27 + 1

-18

Hence;

(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18

7 0
2 years ago
PLEASE HELP ME!! THANK YOU!!
Tems11 [23]

9514 1404 393

Answer:

  [-4,3]

Step-by-step explanation:

The domain is the left-right (horizontal) extent of the function. The dots at the end of the continuous line are solid, so the brackets on the interval are square brackets.

The left dot is at x=-4; the right dot is at x=3, so the domain is ...

  [-4,3]

4 0
2 years ago
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