Answer:
The sum of the first 47 terms of the given series = 6016
Step-by-step explanation:
Given the sequence
13, 18, 23, ...
An arithmetic sequence has a constant difference 'd' and is defined by
As the difference between all the adjacent terms is the same.
so
Arithmetic sequence sum formula
Put the values
Thus, the sum of the first 47 terms of the given series = 6016
Answer:
Step-by-step explanation:
its A
Answer:
BCE
Step-by-step explanation:
I hoped this helped and mark me as brainly pls
<h3>
Answer: Choice B</h3>
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Explanation:
The rule we use is
![\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m](https://tex.z-dn.net/?f=%5CLarge%20a%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20%5Cleft%28%5Csqrt%5Bn%5D%7Ba%7D%5Cright%29%5Em)
where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).
So for instance,
![\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3](https://tex.z-dn.net/?f=%5CLarge%202%5E%7B3%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7B2%5E3%7D%20%3D%20%5Cleft%28%5Csqrt%5B4%5D%7B2%7D%5Cright%29%5E3)
or in this case,
![\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5](https://tex.z-dn.net/?f=%5CLarge%20t%5E%7B5%2F8%7D%20%3D%20%5Csqrt%5B8%5D%7Bt%5E5%7D%20%3D%20%5Cleft%28%5Csqrt%5B8%5D%7Bt%7D%5Cright%29%5E5)
Answer:
the two numbers are 16 and -25
Step-by-step explanation:
Let the two numbers be x and y
x+y=-9
x-y=-41
By substitution
y=-9-x
x-(-9-x)=-41
x+9+x=-41
2x=-41-9
2x=-50
x=-25
y=-9-(-25)
y=16
