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dlinn [17]
3 years ago
15

How do you define the rate of change

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0
ROC is often used while speaking about momentum, and it can generally be expressed as a ratio between a change in one variable relative to a corresponding change in another; the rate of change is represented by the slope of a line.

i hope this helps :)
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One of the numbers increased by 10. How did the average of the two numbers change?
bezimeni [28]

Hello from MrBillDoesMath!

Answer:

The average is increased by 5

Discussion:

Let x be one number and y the other number.

Average of x,y =    (1/2) ( x + y)

if, say, x is increased by 10 then the average of the numbers is

( ( x+ 10) + y) /2

= (x+y)/2 + 10/2                  => (x+y)/2 is the average of the original numbers

= (x+y)/2 + 5

So the average is increased by 5

Thank you,

MrB

3 0
4 years ago
Read 2 more answers
2 5/7+4 3/5= help please
Ainat [17]

Answer:

7\frac{11}{35}

Step-by-step explanation:

2\frac{5}{7}+4\frac{3}{5}

add the whole numbers

2+4=6

combine the fractions

\frac{5}{7}+\frac{3}{5}

LCM is 35 because 7 * 5 =35

\frac{5}{7}=\frac{5\cdot \:5}{7\cdot \:5}=\frac{25}{35}

\frac{3}{5}=\frac{3\cdot \:7}{5\cdot \:7}=\frac{21}{35}

\frac{25}{35}+\frac{21}{35}=\frac{25+21}{35}

=\frac{46}{35}

change the improper fraction into mixed number

6+1\frac{11}{35}

=7\frac{11}{35}

3 0
4 years ago
Richard has 5 markers in a backpack. One of them is black and one is red. Find the probability Richard will reach into the backp
SpyIntel [72]

!/5x1/5 =2/5

!/5 one possible of the total of 5

Multiply both

4 0
4 years ago
I need help ASAP this is 5th Grade Math!
jeyben [28]

Answer:

Yes there is enough.

Step-by-step explanation:

There is 992 computers, you divide 992 by 90 (90 schools) and you would get 11. There would 11 computers for each school.

8 0
3 years ago
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A Rectangular Prism has a volume of 577.2 cubic feet. The prism is 5.2 feet long and 7.4 feet wide. what is the height of the pr
Mama L [17]

The height is 15 feet

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3 years ago
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