Answer:
The speed of jet in still air is 750 miles per hour and speed of wind is 130 miles per hour.
Step-by-step explanation:
Given that:
Distance traveled by jet against the wind = 2480 miles in 4 hours
Combined speed = =
Combined speed = 620 miles per hour
Distance traveled with wind = 7040 miles in 8 hours
Combined speed =
Combined speed = 880
Let,
Speed of jet = x
Speed of wind = y
When jet travels against the wind, the speed will be subtracted
x-y=620 Eqn 1
When jet travels with the wind, the speed will be added
x+y=880 Eqn 2
Adding Eqn 1 and 2
(x-y)+(x+y)=620+880
x-y+x+y=1500
2x=1500
Dividing both sides by 2
Putting x=750 in Eqn 2
750+y=880
y=880-750
y=130
Hence,
The speed of jet in still air is 750 miles per hour and speed of wind is 130 miles per hour.
Answer:
in y = mx + b the gradient is m
in y = 4 - 5x = -5x + 4 the gradient is -5
Step-by-step explanation:
right.
and therefore c is in this case the name of the variable in the equation (or function).
add on.
ah, do you mean (and does this strange problem description mean) that you want the reverse formula : to get C out of F ?
in that case
F = 1.8c + 32 = 9/5 × c + 32
F - 32 = 9/5 × c
5/9 × (F - 32) = c
or
c = 5/9 × (F - 32)
that's it.
X is still 48° because they are both the same angle, just split in half.