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3 years ago

Guys I need help asap!

Mathematics

1 answer:

NeTakaya3 years ago

7 0

Y=13x+5 has: (0,5) (-2,-21)
Y=-3x has: (0,0) (-5,-15) (-3,9)
Y=x-10 has: (8,-2)

Explanation:
You can just substitute the points into the expression. (X,Y) this is the point so you would put the first number in the X slot and the second in the Y slot. If the X half equals the Y half of the equation that point fits in the equation.

You might be interested in

Rewrite the equation by completing the square 4x^2-4x+1=0

oee [108]

Answer:

4(x - $\frac{1}{2}$ )² = 0

Step-by-step explanation:

Given

4x² - 4x + 1 = 0

To complete the square the coefficient of the x² term must be 1

Factor out 4 from 4x² - 4x

= 4(x² - x) + 1 = 0

add/subtract ( half the coefficient of the x- term )² to x² - x

4(x² + 2(- $\frac{1}{2}$ )x + $\frac{1}{4}$ - $\frac{1}{4}$ ) + 1 = 0

4(x - $\frac{1}{2}$ )² - 1 + 1 = 0

4(x - $\frac{1}{2}$ )² = 0

8 0

3 years ago

Read 2 more answers

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

Helppppp pleaseeeeee

Alex73 [517]

Answer:

6 ft

Step-by-step explanation:

6^3 = 216

4 0

3 years ago

Which expressions are equivalent to 2^5 2^4

KIM [24]

Answer with explanation:

The given expression is

$=2^5 \times 2^4$

→As, multiplication of real number follows Commutative property.

Which states that, if a and b are any two real numbers , then

a × b= b × a

The Expression equivalent to ,the above expression are

$1. 2^4 \times 2^5\\\\ 2. 2^5=32 \text{and} 2^4=16, \text{So} 2^5 \times 2^4=32 \times 16=512$

5 0

3 years ago

Read 2 more answers

Solve for x 16x = 20(12)

marysya [2.9K]

Answer: X=15

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

Hope this helps!! :)

4 0

3 years ago

Guys I need help asap!​

Guys I need help asap!