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3 years ago

Round 1.983 to the nearest hundredth

Mathematics

1 answer:

svet-max [94.6K]3 years ago

4 0

Answer:

1.98

Step-by-step explanation:

Find the number in the hundredth place 8 and look one place to the right for the rounding digit 3. Round up if this number is greater than or equal to 5 and round down if it is less than 5.

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The director of the library believes that 14% of the library's collection is checked out. If the director is right, what is the

Ksivusya [100]

Answer: 0.2643

Step-by-step explanation:

Let p be the population proportion and $\hat{p}$ be the sample proportion .

As per given question , we have

$p=0.14\\\\ \hat{p}=0.13\\\\ n=478$

z-score : $\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

$z=\dfrac{0.13-0.14}{\sqrt{\dfrac{0.14(1-0.14)}{478}}}\\\\=-0.630087269176\approx-0.63$

The required probability ( using z-table ):-

$P(z$

Hence, the probability that the proportion of books checked out in a sample of 478 books would be less than 13% = 0.2643

5 0

4 years ago

Best decimal equivalent to 5/8

Igoryamba

The best decimal equivalent is 10/16

6 0

3 years ago

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I'd like some help, thanks!

Otrada [13]

It is likely D I am not positive

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3 years ago

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To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine foun

QveST [7]

Answer:

We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 31.7 milligrams

Sample mean, $\bar{x}$ = 28.5 milligrams

Sample size, n = 9

Alpha, α = 0.05

Sample standard deviation, s = 2.8 milligrams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 31.7\text{ milligrams}\\H_A: \mu < 31.7\text{ milligrams}$

We use One-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{28.5 - 31.7}{\frac{2.8}{\sqrt{9}} } = -3.429$

Now, $t_{critical} \text{ at 0.05 level of significance, 8 degree of freedom } = -1.860$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and accept the alternate hypothesis. We conclude that the mean nicotine content is less than 31.7 milligrams for this brand of cigarette.

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3 years ago

The table gives two options for online music clubs which is also given by the system of equations: y = 0.4x + 15 and y = 0.2x +

geniusboy [140]

The correct answer is D

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3 years ago

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