For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.
Feel free to ask further questions!
Answer:
AB = 6.5
Step-by-step explanation:
C = 59°
AC = 7
CD = 6
AB = ?
Apply the Law of Cosines, which is AB² = AC² + CD² - 2(AC)(CD)*Cos(C)
AB² = 7² + 6² - 2(7)(6)*Cos(59)
AB² = 85 - 43.26
AB² = 41.74
AB = √41.74
AB = 6.5 (nearest tenth)
Answer:
181 mi^2
Step-by-step explanation:
Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;
Dimensions of small rectangle, in the middle of the diagram, are 4 mi by 5 mi, or 20 mi^2; area is 20 mi^2.
Dimensions of circle: r = 12 mi; area of quarter circle is (1/4)(3.14)(12 mi)^2, or 113 mi^2.
Total area is 113 mi^2 + 20 mi^2 + 48 mi^2, or 181 mi^2
