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Rama09 [41]
3 years ago
5

Which of the follong is the process of finding the factors of mathematical expression 2d²-8d​

Mathematics
1 answer:
zhenek [66]3 years ago
6 0

Answer:

2d(d - 4)

Step-by-step explanation:

Given

2d² - 8d ← factor out the common factor of 2d from each term

= 2d(d - 4) ← in factored form

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Please help due today!
katrin [286]
So the first two line segments added together equals the full line segment. So, 8y + 5 + 7y = 13y + 25

15y + 5 = 13y + 25

2y = 20

y = 10
6 0
3 years ago
steve has 75.50$ to spend at the movies. His ticket is 45.50? and he gets a large popcorn and soda. If the popcorn and soda each
Maru [420]
$15. 75.5 - 45.5 = 30.

30/2 = 15
5 0
3 years ago
if you spent $43.78 on an outfit for the dance and you gave the the sales clerk $50.00 how much change should you expect to rece
madreJ [45]

Answer:

6.22

Step-by-step explanation:

use the standard algorithm

3 0
3 years ago
Find x A. 212√2 B. 212–√ C. 213√2 D. 7
victus00 [196]

The value of x in the triangle is (d) 7

<h3>How to solve for x?</h3>

The complete question is in the attached image.

From the attached image of the triangle, we can see that the triangle is a right triangle, and x can be solved using the following sine function

\sin(45) = \frac{x}{7\sqrt 2}

Evaluate sin(45)

\frac 1{\sqrt 2} = \frac{x}{7\sqrt 2}

Solve for x

x = \frac{7\sqrt 2}{\sqrt 2}

Divide

x = 7

Hence, the value of x in the triangle is (d) 7

Read more about special triangles at:

brainly.com/question/654982

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7 0
1 year ago
Find three consecutive integers such as two times the first integer, plus three times the second integer, minus the third intege
NikAS [45]

The three consecutive integers are 5, 6, and 7.

What are consecutive integers?

Whole numbers that follow one another without a gap are known as consecutive integers. A few examples of consecutive integers are 15, 16, and 17, 1,2 and 3, and so on.

Finding the Consecutive Integers

Let the three consecutive integers be a, a + 1, and a + 2.

These three consecutive integers are to be such that two times the first integer when added to three times the second integer minus the third integer, it is equal to 21.

⇒ 2a + 3(a+1) - (a+2) = 21

2a + 3a + 3 - a -2 = 21

5a - a + 3 - 2 = 21

4a + 1 = 21

4a = 20

a = 20/4

a = 5

∴ a+1 = 5+1

a+1 = 6

And, a+2 = 5 + 2

a +2 =7

Hence, the three consecutive integers come out to be 5, 6, and 7

Learn more about consecutive integers here:

brainly.com/question/1767889

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8 0
2 years ago
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