The margin of error for a sample proportion is given by

where:

is the z score associated with the confidence level, p is the sample prortion and n is the sample size.
We assume a confidence level of 95%, then
p = 52% = 0.52 and n = 2251
Therefore, margin of error =

The the interval that is likely to contain the true population proportion is between 49.9% and 54.1%.
Answer:

<h3>First answer is correct</h3>
Step-by-step explanation:

Answer:
283.3%
Step-by-step explanation:
6.8 divided by 2.4 = 2.83333333333
2.8333 x 100 = 283.33
= 283.3%
Answer:
1006.72
Step-by-step explanation:
Multiply 9.68 by 104