✍️ thought challenge...

Write an equation if the line that passes through (0,-3) and (3,3) .

liq [111]

Answer:

y = 2x - 3

Step-by-step explanation:

y = mx + b

m = (y2-y1)/(x2-x1)

m = (3-(-3))/(3-0)

m = 6/3

m = 2

y = mx + b

y = 2x + b

3 = 2(3) + b

3 = 6 + b

b = -3

therefore

y = 2x - 3

6 0

3 years ago

Is this true or no plz help

il63 [147K]

Im pretty sure its No.

7 0

3 years ago

One lap around the lake is 7/10 mile Dasha runs 9 laps around the lake

Sindrei [870]

Answer:

6.3

Step-by-step explanation: Divide 7 by 10 and get .7 then you would multiply that by 9 and youll get 6.3

4 0

4 years ago

A mutual fund company offers its customers a variety of funds: a money-market fund, three different bond funds (short, intermedi

bagirrra123 [75]

Answer:

a. 7% probability that the selected individual owns shares in the balanced fund.

b. 31% probability that the individual owns shares in a bond fund.

c. 58% probability that the selected individual does not own shares in a stock fund

Step-by-step explanation:

a. What is the probability that the selected individual owns shares in the balanced fund?

7% of the individuals owns shares in the balanced fund, so 7% probability that the selected individual owns shares in the balanced fund.

b. What is the probability that the individual owns shares in a bond fund?

Bond funds (short, intermediate, and long-term):

15%(short-term) + 11%(intermediate-term) + 5%(long-term)

15%+11%+5% = 31%

31% probability that the individual owns shares in a bond fund.

c. What is the probability that the selected individual does not own shares in a stock fund?

Anything but moderate and high risk stock%.

The sum of all probabilities is 100%.

18% + 24% = 42% own stock fund.

100 - 42 = 58%

58% probability that the selected individual does not own shares in a stock fund

3 0

3 years ago

a statistics professor finds that when he schedules an office hour at the 10:30a, time slot, an average of three students arrive

Veseljchak [2.6K]

Answer:

The probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

Step-by-step explanation:

Let X = number of students arriving at the 10:30 AM time slot.

The average number of students arriving at the 10:30 AM time slot is, λ = 3.

A random variable representing the occurrence of events in a fixed interval of time is known as Poisson random variables. For example, the number of customers visiting the bank in an hour or the number of typographical error is a book every 10 pages.

The random variable X is also a Poisson random variable because it represents the fixed number of students arriving at the 10:30 AM time slot.

The random variable X follows a Poisson distribution with parameter λ = 3.

The probability mass function of X is given by:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...,\ \lambda>0$

Compute the probability of X = 2 as follows:

$P(X=2)=\frac{e^{-3}3^{2}}{2!}=\frac{0.0498\times 9}{2}=0.2241$

Thus, the probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

6 0

4 years ago

Read 2 more answers