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3 years ago

Kelko wrapped 20 gifts. Keiko wrapped 4 times as many gifts as Henry. Let be the number of gifts that Henry wrapped.

Mathematics

1 answer:

sergey [27]3 years ago

3 0

Answer:

20 = 4n

n = 5

Step-by-step explanation:

Given that :

Number of gifts Keiko wrapped = 20

Let number of gifts wrapped by Henry = n

Keiko wrapped 4 times as many gifts as Henry

Hence,

20 = 4n

The equation that relates the number of gifts wrapped is :

20 = 4n

To obtain n ;

Divide both sides by 4 to isolate n

20/ 4 = 4n / 4

5 = n

Hence,

n = 5

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Answer:

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Step-by-step explanation:

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3 years ago

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shusha [124]

Answer:

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(2/5)*b+1+11 = 0

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Step-by-step explanation:

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2 years ago

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What is the common ratio for the geometric sequence? 32, 8, 2, 12, ... Enter your answer in the box.

mamaluj [8]

Answer:

Given sequence is not a geometric progression and there will be no common ration for this sequence.

Step-by-step explanation:

Need to determine common ration for the following geometric sequence

32, 8, 2, 12, ...

In given geometric sequence

a1 = 32, a2=8, a3=2, a4=12 ……….

Common ratio = $\frac{a_2}{a_1} =\frac{a_3}{a_2} =\frac{a_4}{a_3}$

$\frac{a_2}{a_1}=\frac{8}{32}=\frac{1}{4}$

$\frac{a_3}{a_2} =\frac{2}{8}=\frac{1}{4}$

$\frac{a_4}{a_3}=\frac{12}{2}=6$

Since $\frac{a_2}{a_1}=\frac{a_3}{a_2}\neq\frac{a_4}{a_3}$ so we can say that given sequence is not a geometric progression and there will no no common ration for this sequence.

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3 years ago

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Answer:

Given:

The distances, in yards, that a team moves on its first five plays are 2, 21, 4, 3, and 25.

Solved:

1. The greatest number is 25

2. If the moved distances are square, which one is largest?

3. The move which is greater than 4 is considered "big play"

=> 21 and 25 are big play (21 > 4, 25 > 4)

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Firlakuza [10]

Answer:

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Step-by-step explanation:

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