Answer:
A quotient is the number we get when we divide one number by another.
for example
8 ÷ 4 = 2. In this case, the number 2 will be the quotient since it is the result we got when we divided 8 and 4.
I'm going to assume that "1,457 . 47 =" was meant to have a division sign, if that is the case then the answer is B 31.
Answer:
You have written 26 pages in total.
Step-by-step explanation:
I always enjoyed adding fractions. Something about it is so... <em>simple.</em>
<u>The problem is basically asking us to add 20 1/2 and 5 1/2 together.</u>
I would first suggest adding both halves together, to make 1.
That way, we're left with 20 + 5 + 1. That seem easier, doesn't it?
Then we would add 20, 5 and 1 together, to get 26 whole pages.
And that, to an extent, is how I did it.
Hope this helps! :D
Answer and Explanation:
<em>Solving 3x + 2y = 9 for y gives y = -(3/2)x + (9/2).
</em>
Complete Question
A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?
Answer:
The value required is
Step-by-step explanation:
From the question we are told that
The upper specification is 
The lower specification is
The sample mean is
The standard deviation is 
Generally the capability index in mathematically represented as
![Cpk = min[ \frac{USL - \mu }{ 3 * \sigma } , \frac{\mu - LSL }{ 3 * \sigma } ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7BUSL%20-%20%20%5Cmu%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%20%2C%20%20%5Cfrac%7B%5Cmu%20-%20LSL%20%7D%7B%203%20%2A%20%20%5Csigma%20%7D%20%5D)
Now what min means is that the value of CPk is the minimum between the value is the bracket
substituting value given in the question
![Cpk = min[ \frac{1.68 - 1.6 }{ 3 * 0.03 } , \frac{1.60 - 1.52 }{ 3 * 0.03} ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%20%5Cfrac%7B1.68%20-%20%201.6%20%7D%7B%203%20%2A%20%200.03%20%7D%20%20%2C%20%20%5Cfrac%7B1.60%20-%20%201.52%20%7D%7B%203%20%2A%20%200.03%7D%20%5D)
=> ![Cpk = min[ 0.88 , 0.88 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%200.88%20%2C%200.88%20%20%5D)
So

Now from the question we are asked to evaluated the value of standard deviation that will produce a capability index of 2
Now let assuming that

So

=> 
=> 
So

=> 
Hence
![Cpk = min[ 2, 2 ]](https://tex.z-dn.net/?f=Cpk%20%20%3D%20%20min%5B%202%2C%202%20%5D)
So

So
is the value of standard deviation required
Answer:
c,-0.45 ,
e. 1.16
g. 5/3
h. √2
Cannot be probability.
Step-by-step explanation:
Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.
0≤P(A)≤1
Any value outside this boundaries cannot be probability.
Therefore, -0.45,1.16,5/3 and √2 cannot be probability.