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3 years ago

Seven times the difference of x and 4 is -10

Mathematics

1 answer:

4vir4ik [10]3 years ago

7 0

Answer:

In this equation x = 2

Step-by-step explanation:

First, it is easiest to convert these words to numbers. That would make it

4 - x · 7 = -10

First subtract 4 from both sides.

4 - x · 7 - 4 = - 10 - 4

Then you simplify.

-x · 7 = -14

Divide both sides by 7.

$\frac{-x(7)}{-7} = \frac{-14}{-7}$

Then you simplify that fraction to 2 and thats how you get your answer.

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3 years ago

What is the zero of the function, y = -1/4x + 5 and describe the location of the x-intercept on the coordinate plane.

Anon25 [30]

Answer:

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3 years ago

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

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2 years ago

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Alik [6]

Not sure if this is what you mean but this is what I got.

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3 years ago

Connor wants to attend the town carnival. The price of admission to the

Vesna [10]

Answer:

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Step-by-step explanation:

16 = 0.79x + 4.5

11.5 = 0.79x

x = 14.55 or 14

rounding down because it can't go over $16.

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3 years ago