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2 years ago

Find the amount and the compound interest on 62500 for1*1/2 years at 8% compounded half-yearly

1 answer:

3 0

principal (p)=62500,Time (T)=1.5 years,Rate (R)=8% Ammount=p (1+R÷100) =62500 × 1.1664 =72900 again, compound interest = p(1+R÷100)-1=62500×0.1664 = 10400

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Can someone help please?!! Major Help Pic above

Mila [183]

I believe it’s c. I hope that this is helpful!

8 0

3 years ago

Answer answer it it it

lakkis [162]

Answer:

May-June

Step-by-step explanation:

Notice that:

● during April-May period the Badminton memberships rate of increase is greather then Swimming's since the graph of Badminton is showing a faster increase.

● During June-July period, both functions are decreasing so this period does not satisfy our condition.

● During May-June The Swimming memberships growed faster than Badminton's so its rate of increase is greather than Badminton's.

● during August-September period, The swimming memeberships are increasing slower than Badminton's

So the answer is May-June

8 0

3 years ago

A right rectangular prism is shown.

8_murik_8 [283]

Your answer is 3.7!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

6 0

3 years ago

Given the vector equation ????(t)=(4−3t)????+(−5+t)????+(3−t)????, rewrite this in terms of the parametric equations for the lin

Anit [1.1K]

Answer:

The parametric equations for the line.x(t)=

y(t)=

z(t)=

$\= r (t) = \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}} \atop {z(t)=3-t}} \right \}$

Step-by-step explanation:

From the question we are told that

the given equation is

$\= r(t) = (4-3t) + (-5 + t) + (3-t)$

This given equation can be represented as

$\= r (t) = [4 -3t , -5+t,3-t]$

Generally this equation can be represented in terms of the parametric equations as follows

$\= r (t) = \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}} \atop {z(t)=3-t}} \right \}$

This above equation is obtained by assigning each component of r(t) to each line

4 0

3 years ago

Find the inverse function of f(x)=-4x-10

Dvinal [7]

$f(x)=-4x-10\\
y=-4x-10\\
-4x=y+10\\
x=-\frac{1}{4}y-\frac{5}{2}\\
f^{-1}(x)=-\frac{1}{4}x-\frac{5}{2}$

6 0

3 years ago