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kaheart [24]
3 years ago
9

...hey what's

lign="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Novosadov [1.4K]3 years ago
8 0

Answer:

<em>the</em><em> </em><em>square</em><em> </em><em>root</em><em> </em><em>of</em><em> </em><em>1</em><em> </em><em>is</em><em> </em><em><u>1</u></em><em><u>.</u></em> hope this helps

blsea [12.9K]3 years ago
7 0
1
hope that helps!!!!!
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A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
Please help me with this question <br><br> image attached
user100 [1]
I think the answer is 24
3 0
3 years ago
Read 2 more answers
) Which expressions are equivalent to 45? Choose ALL that apply.
VMariaS [17]
4.5 and maybe 16-64. If they count -
5 0
3 years ago
The product of two consecutive odd integers is 143 find their sum
Alexus [3.1K]
11*13=143
11+13=24
The sum of the two consecutive odd integers is 24
5 0
3 years ago
What is the area of a regular nonagon (9 sides) with side length of 15 cm and apothem of 20.6 cm? Round the answer to the neares
Triss [41]
We know that

<span>The nine radii of a regular Nonagon divides into 9 congruent isosceles triangles
</span>therefore
[the area of <span>a regular nonagon]=9*[area of isosceles triangle]

</span>[area of isosceles triangle]=b*h/2------> 15*20.6/2----> 154.5 cm²
so
[the area of a regular nonagon]=9*[154.5]------> 1390.5 cm²

the answer is
1390.5 cm²

5 0
3 years ago
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