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3 years ago

9

...hey what's

lign="absmiddle" class="latex-formula">

2 answers:

Novosadov [1.4K]3 years ago

8 0

Answer:

<em>the</em><em> </em><em>square</em><em> </em><em>root</em><em> </em><em>of</em><em> </em><em>1</em><em> </em><em>is</em><em> </em><em><u>1</u></em><em><u>.</u></em> hope this helps

blsea [12.9K]3 years ago

7 0

1
hope that helps!!!!!

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#!). Two planes leave New York at 10am, One heading for Europe at 600mph and one heading in the opposite direction at 150mph. At

timurjin [86]

Speed = Distance / time

Distance = Speed x time

In t hours, first plane travels = 600 t miles

In t hours, the second plane travels =150 t miles

After t hours the distance between the two planes is:

(600t+150t)= 750t ( since both travel in opposite directions)

When the distance is 900 miles:

750t= 900

Solve for t:

t= 900/750

t= 1.2 hours

After 1.2 hours.

1.2 x 60 = 72 minutes = 60 +12 = 1 hour and 12 minutes

Since both leave at 10 pm:

10am + 1 hour and 12 minutes : 11:12 am

They will be 900 miles apart at 11:12 am

Each one traveled:

Plane 1:

Distance: Speed x time = 600 mph x 1.2 = 720 miles

Plane 2:

Distance = Speed x time = 150 mph x 1.2 = 180 miles

6 0

1 year ago

Cuboid ABCDEFGH is shown

gtnhenbr [62]

Answer:

The angle formed between CF and the plane ABCD is approximately 47.14°

Step-by-step explanation:

The given parameters are;

BC = 6.8

DE = 9.3

∠BAC = 52°

We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;

sin∠BAC = BC/(The length of a line drawn from A to C)

∴ The length of the line drawn from A to C = BC/sin∠BAC

The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63

∴ AC = 8.63

By trigonometry, we have;

The angle formed between CF and the plane ABCD = Angle ∠ACF

$tan\angle X = \dfrac{Opposite \ leg \ length}{Adjacent\ leg \ length}$

$tan\angle ACF = \dfrac{FA}{AC}$

In a cuboid, FA = BG = CH = DE = 9.3

$\therefore tan\angle ACF = \dfrac{9.3}{8.63}$

$\therefore \angle ACF = arctan \left(\dfrac{9.3}{8.63} \right) \approx 47.14^{\circ}$

The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°

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3 years ago

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Since the total is 42 divide by two since they are the same length so it would be 21

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if the side length of the cube is 5 inches the volume of the cube is how many cubic inches and its total surface area is how man

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