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larisa86 [58]
2 years ago
9

Helpppppppppppppppppppppppppp me owo plzzzzzzzzzz

Mathematics
2 answers:
Tanya [424]2 years ago
8 0

Answer:

Just concentrate you can do it

Step-by-step explanation:

Inga [223]2 years ago
6 0

Answer:

(-8x^2+7x-7)-(10x^2-10x+2)\\-8x^2+7x-7-10x^2+10x-2\\-8x^2-10x^2+7x+10x-7-2\\-18x^2+17x-9

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Which one should I choose?
Nastasia [14]

Given:

A figure of a quadrilateral.

To find:

The measures of angle 1 and angle 2.

Solution:

The given figure has two pairs of congruent adjacent sides. So, the quadrilateral in the figure is a kite.

We know that the diagonals of a kit are perpendicular to each other at the point of intersection.

m\angle 1=90^\circ

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

90^\circ+65^\circ+m\angle 2=180^\circ

155^\circ+m\angle 2=180^\circ

m\angle 2=180^\circ-155^\circ

m\angle 2=25^\circ

Therefore, the correct option is C.

7 0
3 years ago
How do I solve question 2?
sdas [7]

you multiply the number of years

6 0
2 years ago
Use the Midpoint Rule and the given data to estimate the value of the integral I. (Give the answer to two decimal places.)
svlad2 [7]

Answer:

a) integral = 24.72

b) |Error| ≤ 0.4267

Step-by-step explanation:

a)

The integral:

\int_{0}^{3.2} f(x) dx

can be  approximated with the midpoint rule, as follows:

6.7*(0.8 - 0.0) + 8.9*(1.6 - 0.8) + 6.9*(2.4-1.6) + 8.4*(3.2 - 2.4) = 24.72

(that is, all the intervals are 0.8 units length and f(x) is evaluated in the midpoint of the interval)

b)The error bound for the midpoint rule with <em>n</em> points is:

|Error| ≤ K*(b - a)^3/(24*n^2)

where <em>b</em> and are the limits of integration of the integral and K = max |f''(x)|

Given that -5 ≤ f''(x) ≤ 1, then K = 5.  Replacing into the equation:

|Error| ≤ 5*(3.2 - 0)^3/(24*4^2) = 0.4267

5 0
2 years ago
Which equation in standard form has a graph that passes through the point (-4 , 2) and has a slope of 9/2?
malfutka [58]
Answer is <span>C. 9x-2y=-40

hope that helps

because y = 9/2x +20 then 2y = 9x + 40 so 9x -2y = -40
</span>
8 0
3 years ago
Help me i need to submit to my teacher by 8pm​
Vladimir [108]

Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral.  r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 -  (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it.  I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

7 0
3 years ago
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