Answer:
Gusion = 2years
Lesley= 40years
Step-by-step explanation:
Let Guison age be x
Let Lesley age be y
If the sum of the ages of Gusion and Lesley is 42, then;
x+ y =42 ... 1
Four years ago
Guison age = x - 4
Lesley age = y - 4
If four years ago, Gusion was twice as old as Lesley, then;
x - 4 = 2(y-4)
x - 4 = 2y - 9
x - 2y = -9+4
x - 2y = -5 .... 2
Substract 1 from 2;
y + 2y = 1+5
3y = 6
y = 2
From 1;
x = 42 - y
x = 42-2
x = 40
Hence present age pf Guison is 2 years
Present age of Lesley is 40 years
Answer:
You need to show us the options
Step-by-step explanation:
The number of permutations of objects from objects is .
The number of ways of choosing 3 digits from 6 digits without replacement ( order is important) is . This is the number of all possible permutations of choosing 3 from 6.
Correct choice is 120.
Answer:
36x-3y+4z^2+26-7x^2
Step-by-step explanation:
Okay well for starters, you can't subtract that because it's an expression, not an equation. And secondly, there was '?' which I'm going to assue=me was a typing error.
Now to actually simplify this mess of an expression, you just need to combine the like-terms! Once you do that you really can't do anything else, since you don't know the varibles.
Answer:
7/10 or 70%
Step-by-step explanation:
There has to be at least two T in each result of the simulation. This means you can also have 3 T's and 4 T's in the result.
These are the results that qualify as having at least two T's.
1. TTTT, 2. TTTT, 3. THTH, 4. HTTT, 5. TTTT, 7. HTHT, 9. THTH
That is 7 out of the 10 results which is 7/10 or 70%